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请问Oracle窗口函数求当前时间向前推30天的平均值?

热度:7   发布时间:2016-04-24 07:31:26.0
请教Oracle窗口函数求当前时间向前推30天的平均值?急急!
如题。数据大致如下:
  日期 数值
20121129 2
20121129 1
20121129 3
20121130 4
20121130 3
20121130 1
20121130 2
20121201 3
20121201 2
20121201 1
20121202 3
20121202 4
20121202 2
20121202 1
20121211 3
20121211 2
20121211 1
20121212 1
20121212 2
20121212 3
20121212 4
使用窗口函数写法如下:
SELECT tef.日期,AVG(SUM(tef.数值)) OVER (PARTITION BY tef.日期 ORDER BY TRUNC(TO_DATE(tef.日期,'yyyy-mm-dd'))
RANGE BETWEEN INTERVAL '30' DAY preceding AND INTERVAL '0' DAY following ) tstst
 FROM 表 tef 
GROUP BY tef.日期
;
使用这种写法向前30天由于日期不连续,只能获取连续日期的数据,比如20121212只能汇总20121211+20121212的数据无法汇总到20121202的数据,请教如何修改语句获取连续日期的数据汇总满足需求?

------解决方案--------------------
探讨

测试数据:
SQL code

CREATE TABLE T168
(
MyDate DATE,
MyNum NUMBER(4)
);
INSERT INTO T168 VALUES(to_date('20121129', 'YYYYMMDD'), 1);
INSERT INTO T168 VALUES(to_date('20121129', 'YYYYMMDD'), 2)……

------解决方案--------------------
比较好懂的方法 获取前30天每天的平均值
SQL code
with t1 as (select '1' 编号,'20121127' 日期,'2' 数值 from dual union allselect '2',  '20121128','1' from dual union allselect '3',  '20121129','3' from dual union allselect '4',  '20121130','4' from dual union allselect '5',  '20121130','3' from dual union allselect '6',  '20121130','1' from dual union allselect '7',  '20121130','2' from dual union allselect '8',  '20121201','3' from dual union allselect '9',  '20121201','2' from dual union allselect '10', '20121202','2' from dual union allselect '11', '20121203','2' from dual union allselect '12', '20121204','2' from dual union allselect '13', '20121205','2' from dual union allselect '14', '20121206','4' from dual union allselect '15', '20121207','3' from dual union allselect '16', '20121208','6' from dual union allselect '17', '20121209','7' from dual union allselect '18', '20121210','3' from dual union allselect '19', '20121211','5' from dual union allselect '20', '20121212','2' from dual union allselect '21', '20121213','2' from dual union allselect '22', '20121214','2' from dual union allselect '23', '20121215','2' from dual union allselect '24', '20121216','2' from dual union allselect '25', '20121217','2' from dual union allselect '26', '20121218','2' from dual union allselect '27', '20121219','2' from dual union allselect '28', '20121220','2' from dual union allselect '29', '20121221','2' from dual union allselect '30', '20121222','2' from dual union allselect '31', '20121223','2' from dual union allselect '32', '20121224','2' from dual union allselect '33', '20121225','2' from dual union allselect '34', '20121226','2' from dual union allselect '35', '20121227','2' from dual union allselect '36', '20121228','2' from dual union allselect '37', '20121228','2' from dual union allselect '38', '20121228','2' from dual union allselect '39', '20121228','2' from dual)select t1.日期,avg(sum(t1.数值)/count(t1.数值)) over(partition by t1.日期 order by t1.日期) a_count from t1,(    select 日期,rownum from     (        select distinct 日期        from t1        order by 日期    )    where rownum<=30) t2where t1.日期 in t2.日期group by t1.日期order by t1.日期        日期      a_count-------------------------------1    20121127    22    20121128    13    20121129    34    20121130    2.55    20121201    2.56    20121202    27    20121203    28    20121204    29    20121205    210    20121206    411    20121207    312    20121208    613    20121209    714    20121210    315    20121211    516    20121212    217    20121213    218    20121214    219    20121215    220    20121216    221    20121217    222    20121218    223    20121219    224    20121220    225    20121221    226    20121222    227    20121223    228    20121224    229    20121225    230    20121226    2
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