ID Value
1 89
1 92
1 78
2 96
2 99
3 72
3 94
4 88
==========
输出结果
ID Value
1 89
2 96
3 72
4 88
输出结果是每一个分组的第一行，该如何写？
select ID,Value from tab_1
------解决方案--------------------
select ID,Value from tab_1 group by id,Value;
------解决方案--------------------
select sub.id, sub.value from
(with a as (select '1' as ID, '89' as value from dual
union all
select '1','92' from dual
union all
select '1','78' from dual
union all
select '2','96' from dual
union all
select '2','99' from dual
union all
select '3','72' from dual
union all
select '3','94' from dual
union all
select '4','88' from dual)
select id,value,row_number() over (partition by id order by id) cnt from a) sub
where sub.cnt = 1;