表st
sno sname sex
001 jon 1
002 hat 1
003 ww 2
004 qw 1
.
.
.
(1表示男，2表示女)
性别 人数
1 m
2 n
m+n
怎么表示下面这张表
------最佳解决方案--------------------
按性别分组
然后再rollup作个统计啊
sys@ORCL> create table st (sno number,sname varchar2(10),sex number);
Table created.
sys@ORCL> insert into st values(001,'aa',1);
1 row created.
sys@ORCL> insert into st values(002,'bb',1);
1 row created.
sys@ORCL> insert into st values(003,'cc',2);
1 row created.
sys@ORCL> insert into st values(004,'dd',1);
1 row created.
sys@ORCL> commit;
Commit complete.
sys@ORCL> select * from st;
SNO SNAME SEX
---------- ---------- ----------
1 aa 1
2 bb 1
3 cc 2
4 dd 1
sys@ORCL> select sex,count(sex) from st group by rollup(sex);
SEX COUNT(SEX)
---------- ----------
1 3
2 1
4
------其他解决方案--------------------
select sex as 性别, count(*) as 人数 from st group by rollup(sex);
------其他解决方案--------------------
select sex, sum(decode(sex, '1', 1, '2', 1)) from st
------其他解决方案--------------------
如果不行，，，说说。。。我没有试。
please call me Rayn
my QQ is 412552703
------其他解决方案--------------------
group by rollup() 对每组数据进行合计
------其他解决方案--------------------
学习了，之前只用group by，原来还有group by rollup。
------其他解决方案--------------------