- SQL code
--查询某日期区间,未退款且已支付成功的支付记录SELECT service_order,sum(PAYMENT_AMOUNT) FROM PAYMENT A1 WHERE EXISTS( SELECT order_id FROM ctoc_order A2 WHERE 1=1 and A2.order_id=A1.service_order AND (Order_Status =1 OR Order_Status=2) AND trunc(ORDER_CREATE_TIME) between to_date('2012-05-01','yyyy-MM-dd') and to_date('2012-06-01','yyyy-MM-dd'))and payment_status=0group by service_orderhaving sum(PAYMENT_AMOUNT)>0订单表:ctoc_orderid:order_id状态:Order_Status支付表:PAYMENT订单表外键;service_order金额:PAYMENT_AMOUNT--求加速,求优化```
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- SQL code
SELECT service_order,sum(PAYMENT_AMOUNT) FROM PAYMENT A1 WHERE EXISTS( SELECT order_id FROM ctoc_order A2 WHERE 1=1 and A2.order_id=A1.service_order AND (Order_Status =1 OR Order_Status=2) AND trunc(ORDER_CREATE_TIME) between to_date('2012-05-01','yyyy-MM-dd') and to_date('2012-06-01','yyyy-MM-dd'))and payment_status=0group by service_orderhaving sum(PAYMENT_AMOUNT)>0既然你过滤了sum(PAYMENT_AMOUNT)>0是不是开始panment_amount>0的条件就可以写在where那里呢,而不是group by后判断
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1.使用hint,改变or的执行计划。
2.你的date应该可以直接比较吧,不使用trunc,例如数据库中日期 ’2012-1-2 01:01:20‘ 判断它是否在1月付款、退款,不用做时间处理的。
- SQL code
SELECT /*+USE_CONCAT*/ service_order,sum(PAYMENT_AMOUNT) FROM PAYMENT A1 WHERE EXISTS( SELECT order_id FROM ctoc_order A2 WHERE 1=1 and A2.order_id=A1.service_order AND (Order_Status =1 OR Order_Status=2) AND trunc(ORDER_CREATE_TIME) between to_date('2012-05-01','yyyy-MM-dd') and to_date('2012-06-01','yyyy-MM-dd'))and payment_status=0group by service_orderhaving sum(PAYMENT_AMOUNT)>0