ID Value
1 89
1 92
1 78
2 96
2 99
3 72
3 94
4 88
==========
输出结果
ID Value
1 89
2 96
3 72
4 88
输出结果是每一个分组的第一行，该如何写？
select ID,Value from tab_1
------解决方案--------------------
select ID,Value from tab_1 group by id,Value;
------解决方案--------------------
- SQL code
select sub.id, sub.value from(with a as (select '1' as ID, '89' as value from dualunion allselect '1','92' from dualunion allselect '1','78' from dualunion allselect '2','96' from dualunion allselect '2','99' from dualunion allselect '3','72' from dualunion allselect '3','94' from dualunion allselect '4','88' from dual)select id,value,row_number() over (partition by id order by id) cnt from a) subwhere sub.cnt = 1;