数据库表示这样的
id begintime endtime
sql取出是：1001 2014-07-25 00:00:00 2014-07-25 06:00:00
1001 2014-07-25 09:00:00 2014-07-25 12:30:00
1001 2014-07-25 15:00:00 2014-07-25 19:15:00
每隔30分钟拼接好
00:00-00:30
00:30-01:00
.......
18:30-19:00
19:00-19:15
怎么写呢，求助
------解决方案--------------------
with t as
(select 1001 id,
to_date('20140725 00:00:00', 'yyyymmdd hh24:mi:ss') begintime,
to_date('20140725 06:00:00', 'yyyymmdd hh24:mi:ss') endtime
from dual
union all
select 1001 id,
to_date('20140725 09:00:00', 'yyyymmdd hh24:mi:ss') begintime,
to_date('20140725 12:30:00', 'yyyymmdd hh24:mi:ss') endtime
from dual
union all
select 1001 id,
to_date('20140725 15:00:00', 'yyyymmdd hh24:mi:ss') begintime,
to_date('20140725 19:15:00', 'yyyymmdd hh24:mi:ss') endtime
from dual)
select id,to_char(t1,'yyyymmdd hh24:mi:ss')
------解决方案--------------------
'~'
------解决方案--------------------
to_char(t2,'yyyymmdd hh24:mi:ss')
from (select id,
time t1,
lead(time) over(partition by id, rn order by time) t2
from (select id, rn, begintime + (level - 1) * 30 / 24 / 60 time
from (select t.*, rownum rn from t)
connect by prior
begintime + (level - 1) * 30 / 24 / 60 <= endtime
and prior rn = rn
and prior dbms_random.value is not null
union
select id, rownum, endtime
from t))
where t2 is not null;