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NYOJ - Same binary weight

热度:74   发布时间:2024-01-20 17:53:29.0

Same binary weight

时间限制: 300 ms  |  内存限制: 65535 KB
难度: 3
描述

The binary weight of a positive  integer is the number of 1's in its binary representation.for example,the decmial number 1 has a binary weight of 1,and the decimal number 1717 (which is 11010110101 in binary) has a binary weight of 7.Give a positive integer N,return the smallest integer greater than N that has the same binary weight as N.N will be between 1 and 1000000000,inclusive,the result is guaranteed to fit in a signed 32-bit interget.

输入
The input has multicases and each case contains a integer N.
输出
For each case,output the smallest integer greater than N that has the same binary weight as N.
样例输入
1717
4
7
12
555555
样例输出
1718
8
11
17
555557

#include <iostream>
#include <string>
#include <bitset>using namespace std;int main(void)
{unsigned int n;while(cin >> n){bitset <32> bs;   // 使用STL bitset来存储操作数的bit位int m = 0;while(n){if(n&1)bs.set(m);m++;n >>= 1;}int count = 0;for(int i = 0; i < m; i++)   // 寻找到第一个01,将01转换为10。{if(bs.test(i)){count++;bs.reset(i);if(!bs.test(i+1)){bs.set(i+1);break;}}}for(int i = 0; i < count - 1; i++)  // 保持1的数量不变,将其低位全部置为1.{bs.set(i);}cout << bs.to_ulong() << endl;}return 0;
}

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