通过itertools中的groupby进行统计，区间可以自定义，我定义的是10.
from itertools import groupbylst=[]
with open(path,'r',encoding='utf-8') as f:lines=f.readlines()for i,line in enumerate(lines):cnt=int(line.strip())lst.append(cnt)
print(len(lst))
for k,g in groupby(sorted(lst),key=lambda x:x//10):print('{}-{}:{}'.format(k*10,(k+1)*10-1,len(list(g))))