PAT.B1001.害死人不偿命的(3n+1)猜想

C/C++

#include<stdio.h>
int main()
{int a=0, count=0;scanf("%d",&a);for(; a!=1; count++){if(a%2==0)a/=2;else a=(3*a+1)/2;}printf("%d",count);return 0;
}