力扣：LCP 17. 速算机器人

int calculate(char* s)
{/*"A" 运算：使 x = 2 * x + y；"B" 运算：使 y = 2 * y + x。*/int x=1,y=0,i=0;while ( *(s+i) != '\0' )    //检查字符是否结束{if (*(s + i) == 65){x = 2 * x + y;} else {y = 2 * y + x;}i++;}return x+y;
}