python selenium破解极验3滑动验证码，解决物理公式不可用的问题
一、采用物理加速度公式算法
def get_track(self, distance):"""获取滑块移动轨迹的列表:param distance: 第二个缺块的左侧的x坐标:return: 滑块移动轨迹列表"""track = []current = 2mid = distance * 1 / 2mid0 = distance * 1 / 4mid1 = distance * 1 / 8t = 0.2v = 50distance += 10 # 使滑块划过目标地点, 然后回退while current < (distance - 10):if current < mid1:a = random.randint(4, 10)elif current < mid0:a = -random.randint(6, 8)elif current < mid:a = random.randint(4, 10)v0 = vv = v0 + a * ts = v0 * t + 0.5 * a * t * tcurrent += sa = -random.randint(6, 7)track.append(round(s))for i in range(2):track.append(-random.randint(2, 3))for i in range(2):track.append(-random.randint(1, 4))return track
注意此方法已经不可用，会被识别出来，结果会显示图片被怪物吃掉了。
二、采用轨迹离散分布生成的算法
# 轨迹公式，也可采用其他公式 def ease_out_quart(self, x):return 1 - pow(1 - x, 4)def get_tracks_2(self, distance, seconds, ease_func):"""根据轨迹离散分布生成的数学 生成 成功率很高 90% 往上:param distance: 缺口位置:param seconds: 时间:param ease_func: 生成函数:return: 轨迹数组"""distance += 20tracks = [0]offsets = [0]for t in np.arange(0.0, seconds, 0.1):ease = ease_funcoffset = round(ease(t / seconds) * distance)tracks.append(offset - offsets[-1])offsets.append(offset)tracks.extend([-3, -2, -3, -2, -2, -2, -2, -1, -0, -1, -1, -1, -1, -2, -1]) #可以自己按情况改return tracks