例如输入：abcd123.4567.890.123
输出：123.4567.890
“.”可以作为连接符连接两个数字，但是要求"."两边必须都是数字。
面试时遇到的题，因为忽略了对‘0’的处理，所以挂了。
#include<iostream>
#include<stdio.h>#define MAX_SIZE 0x500bool IsDotCorrect(char*szInput, int i, int nLastCmpPos, int nLen)//Check if it's a correct dot.
{if (nLastCmpPos < 0){return false;}if ((i - 1 >= 0 && i + 1 <= nLen - 1 && (szInput[i - 1] >= '0' && szInput[i - 1] <= '9') && (szInput[i + 1] >= '0' && szInput[i + 1] <= '9')) && ((szInput[i + 1] - szInput[nLastCmpPos]) == 1 && szInput[nLastCmpPos] != '0')){return true;}return false;
}
int main()
{char szInput[MAX_SIZE] = { 0 };gets_s(szInput, MAX_SIZE);int nLen = strlen(szInput);int nCount = 0;int nCountPos = 0;bool bIsCount = false;int nLastCmpPos = -1;int nCountBak = 0;int nCountPosBak = 0;for (int i = 0; i < nLen; i++){if (!bIsCount)//Is Count Start{nCountPos = i;}if ((szInput[i] >= '0' && szInput[i] <= '9') || (szInput[i] == '.' && IsDotCorrect(szInput, i, nLastCmpPos, nLen)))//correct char{bIsCount = true;if (szInput[i] == '.')//correct dot ++{nCount++;}else{if (i - 1 >= 0)//if it's first correct char, no need to compare{if (nCount == 0) //first num in this loop ,no need to compare{nCount++;}else{if (((szInput[i] - szInput[nLastCmpPos]) == 1) && szInput[nLastCmpPos] != '0'){nCount++;}else if (szInput[i] == '0' && szInput[nLastCmpPos] == '9'){nCount++;}else{bIsCount = false;}/*if (szInput[i] == '0' && szInput[nLastCmpPos] == '9'){nCount++;}*/}}else//first num ++{nCount++;}nLastCmpPos = i;}if (!bIsCount)//Count start{bIsCount = false;//Count againif (nCountBak <= nCount){nCountBak = nCount;nCountPosBak = nCountPos;}nCountPos = 0;nCount = 0;nLastCmpPos = 0;}}else//incorrect char{bIsCount = false;//Count againif (nCountBak <= nCount){nCountBak = nCount;nCountPosBak = nCountPos;}nCountPos = 0;nCount = 0;nLastCmpPos = 0;}}if (nCountBak <= nCount){nCountBak = nCount;nCountPosBak = nCountPos;}//abcd123.4567.890.123//b12.34.12for (int i = 0; i < nCountBak; i++){printf("%c", *(szInput + nCountPosBak + i));}printf("\n");system("pause");}