Word Pattern
题目描述:
Given a pattern
and a string str
, find if str
follows the same pattern.
Here follow means a full match, such that there is a bijection between a letter in pattern
and a non-empty word in str
.
Examples:
- pattern =
"abba"
, str ="dog cat cat dog"
should return true. - pattern =
"abba"
, str ="dog cat cat fish"
should return false. - pattern =
"aaaa"
, str ="dog cat cat dog"
should return false. - pattern =
"abba"
, str ="dog dog dog dog"
should return false.
Notes:
You may assume pattern
contains only lowercase letters, and str
contains lowercase letters separated by a single space.
题目思路:
用两个哈希表,将两个字符串的对应位置给予相同的映射,如果已有映射不相同,则返回false
题目代码:
class Solution {
public:bool wordPattern(string pattern, string str) {istringstream in(str);map<string,int>table1;map<char, int>table2;int i = 0, n = pattern.length();for(string word; in >> word; i++){if(table2[pattern[i]] != table1[word] || i==n){return false;}else{table1[word] = table2[pattern[i]] = i+1;}}return i==n;}
};