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java hashmap重要源码

热度:23   发布时间:2023-10-22 00:25:51.0
/**  * The default initial capacity - MUST be a power of two.  */ 默认容量 static final int DEFAULT_INITIAL_CAPACITY = 1 << 4; // aka 16

/**  * The maximum capacity, used if a higher value is implicitly specified  * by either of the constructors with arguments.  * MUST be a power of two <= 1<<30.  */ 最大容量 static final int MAXIMUM_CAPACITY = 1 << 30;

/**  * The load factor used when none specified in constructor.  */ 默认负载因子 static final float DEFAULT_LOAD_FACTOR = 0.75f;
/**  * The number of times this HashMap has been structurally modified  * Structural modifications are those that change the number of mappings in  * the HashMap or otherwise modify its internal structure (e.g.,  * rehash). This field is used to make iterators on Collection-views of  * the HashMap fail-fast. (See ConcurrentModificationException).  */ 修改次数(由于hashmap不是线程安全的,由此判断群体操作时的数据安全) transient int modCount;

/**  * The next size value at which to resize (capacity * load factor).  *  * @serial  */ 桶元(容量*负载因子) // (The javadoc description is true upon serialization.
// Additionally, if the table array has not been allocated, this
// field holds the initial array capacity, or zero signifying
// DEFAULT_INITIAL_CAPACITY.)
int threshold;

/**  * The load factor for the hash table.  *  * @serial  */ 负载因子 final float loadFactor;

/**  * Implements Map.put and related methods  *  * @param hash hash for key  * @param key the key  * @param value the value to put  * @param onlyIfAbsent if true, don't change existing value  * @param evict if false, the table is in creation mode.  * @return previous value, or null if none  */ 按照桶元找链表,通过链表寻找对应的Node,没有就创建一个Node final V putVal(int hash, K key, V value, boolean onlyIfAbsent,
               boolean evict) {Node<K,V>[] tab; Node<K,V> p; int n, i;
    if ((tab = table) == null || (n = tab.length) == 0)n = (tab = resize()).length;
    if ((p = tab[i = (n - 1) & hash]) == null)tab[i] = newNode(hash, key, value, null);
    else {Node<K,V> e; K k;
        if (p.hash == hash &&((k = p.key) == key || (key != null && key.equals(k))))e = p;
        else if (p instanceof TreeNode)e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
        else {for (int binCount = 0; ; ++binCount) {if ((e = p.next) == null) {p.next = newNode(hash, key, value, null);
                    if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st
                        treeifyBin(tab, hash);
                    break;
                }if (e.hash == hash &&((k = e.key) == key || (key != null && key.equals(k))))break;
                p = e;
            }}if (e != null) { // existing mapping for key
            V oldValue = e.value;
            if (!onlyIfAbsent || oldValue == null)e.value = value;
            afterNodeAccess(e);
            return oldValue;
        }}++modCount;
    if (++size > threshold)resize();
    afterNodeInsertion(evict);
    return null;
}
/**  * Implements Map.get and related methods  *  * @param hash hash for key  * @param key the key  * @return the node, or null if none  */ 按照桶元( (n-1) & hash )寻找链表,通过链表寻找Node final Node<K,V> getNode(int hash, Object key) {Node<K,V>[] tab; Node<K,V> first, e; int n; K k;
    if ((tab = table) != null && (n = tab.length) > 0 &&(first = tab[(n - 1) & hash]) != null) {if (first.hash == hash && // always check first node
            ((k = first.key) == key || (key != null && key.equals(k))))return first;
        if ((e = first.next) != null) {if (first instanceof TreeNode)return ((TreeNode<K,V>)first).getTreeNode(hash, key);
            do {if (e.hash == hash &&((k = e.key) == key || (key != null && key.equals(k))))return e;
            } while ((e = e.next) != null);
        }}return null;
}
/**  * Basic hash bin node, used for most entries. (See below for  * TreeNode subclass, and in LinkedHashMap for its Entry subclass.)  */ 每一个Key对应的一个Node static class Node<K,V> implements Map.Entry<K,V> {final int hash;
    final K key;
    V value;
    Node<K,V> next;

    Node(int hash, K key, V value, Node<K,V> next) {this.hash = hash;
        this.key = key;
        this.value = value;
        this.next = next;
    }public final K getKey()        { return key; }public final V getValue()      { return value; }public final String toString() { return key + "=" + value; }public final int hashCode() {return Objects.hashCode(key) ^ Objects.hashCode(value);
    }public final V setValue(V newValue) {V oldValue = value;
        value = newValue;
        return oldValue;
    }public final boolean equals(Object o) {if (o == this)return true;
        if (o instanceof Map.Entry) {Map.Entry<?,?> e = (Map.Entry<?,?>)o;
            if (Objects.equals(key, e.getKey()) &&Objects.equals(value, e.getValue()))return true;
        }return false;
    }
}
/**  * Computes key.hashCode() and spreads (XORs) higher bits of hash  * to lower. Because the table uses power-of-two masking, sets of  * hashes that vary only in bits above the current mask will  * always collide. (Among known examples are sets of Float keys  * holding consecutive whole numbers in small tables.) So we  * apply a transform that spreads the impact of higher bits  * downward. There is a tradeoff between speed, utility, and  * quality of bit-spreading. Because many common sets of hashes  * are already reasonably distributed (so don't benefit from  * spreading), and because we use trees to handle large sets of  * collisions in bins, we just XOR some shifted bits in the  * cheapest possible way to reduce systematic lossage, as well as  * to incorporate impact of the highest bits that would otherwise  * never be used in index calculations because of table bounds.  */ 计算一个hash static final int hash(Object key) {int h;
    return (key == null) ? 0 : (h = key.hashCode()) ^ (h >>> 16);
}
/**  * Initializes or doubles table size. If null, allocates in  * accord with initial capacity target held in field threshold.  * Otherwise, because we are using power-of-two expansion, the  * elements from each bin must either stay at same index, or move  * with a power of two offset in the new table.  *  * @return the table  */ 创建或是扩容Node<K,V>[] final Node<K,V>[] resize() {Node<K,V>[] oldTab = table;
    int oldCap = (oldTab == null) ? 0 : oldTab.length;
    int oldThr = threshold;
    int newCap, newThr = 0;
    if (oldCap > 0) {if (oldCap >= MAXIMUM_CAPACITY) {threshold = Integer.MAX_VALUE;
            return oldTab;
        }else if ((newCap = oldCap << 1) < MAXIMUM_CAPACITY &&oldCap >= DEFAULT_INITIAL_CAPACITY)newThr = oldThr << 1; // double threshold
    }else if (oldThr > 0) // initial capacity was placed in threshold
        newCap = oldThr;
    else {               // zero initial threshold signifies using defaults
        newCap = DEFAULT_INITIAL_CAPACITY;
        newThr = (int)(DEFAULT_LOAD_FACTOR * DEFAULT_INITIAL_CAPACITY);
    }if (newThr == 0) {float ft = (float)newCap * loadFactor;
        newThr = (newCap < MAXIMUM_CAPACITY && ft < (float)MAXIMUM_CAPACITY ?(int)ft : Integer.MAX_VALUE);
    }threshold = newThr;
    @SuppressWarnings({
  "rawtypes","unchecked"})Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap];
    table = newTab;
    if (oldTab != null) {for (int j = 0; j < oldCap; ++j) {Node<K,V> e;
            if ((e = oldTab[j]) != null) {oldTab[j] = null;
                if (e.next == null)newTab[e.hash & (newCap - 1)] = e;
                else if (e instanceof TreeNode)((TreeNode<K,V>)e).split(this, newTab, j, oldCap);
                else { // preserve order
                    Node<K,V> loHead = null, loTail = null;
                    Node<K,V> hiHead = null, hiTail = null;
                    Node<K,V> next;
                    do {next = e.next;
                        if ((e.hash & oldCap) == 0) {if (loTail == null)loHead = e;
                            else
                                loTail.next = e;
                            loTail = e;
                        }else {if (hiTail == null)hiHead = e;
                            else
                                hiTail.next = e;
                            hiTail = e;
                        }} while ((e = next) != null);
                    if (loTail != null) {loTail.next = null;
                        newTab[j] = loHead;
                    }if (hiTail != null) {hiTail.next = null;
                        newTab[j + oldCap] = hiHead;
                    }}}}}return newTab;
}