string ls_string,ls_spbm,ls_tradetime,ls_lsj,ls_sl
ls_string=ls_spbm+','+ls_tradetime+','+ls_lsj+','+ls_sl（例如：XXXX,2012-08-08,XXX,XXXXX；时间长度为10，其余字符串长度没限制）
ls_spbm= left(ls_string,pos(ls_string,',')-1)
ls_tradetime= mid(ls_string,pos(ls_string,',')+1,10)
ls_lsj= ?
ls_sl= mid(ls_string,lastpos(ls_string,',')+1)
ls_lsj的值怎么取？
------解决方案--------------------
楼主要拆分逗号分隔的字符串吗？
string ls_yuan,ls[],ls_msg
int li_start,li_end,li_i
ls_yuan="XXXX,2012-08-08,XXX,XXXXX"
ls_yuan=ls_yuan+","
li_start=1
li_end=pos(ls_yuan,",",li_start)
do while li_end<>0
li_i=upperbound(ls[]) + 1
ls[li_i]=mid(ls_yuan,li_start,li_end - li_start)
li_start=li_end+1
li_end=pos(ls_yuan,",",li_start)
loop
for li_i=1 to upperbound(ls[])
ls_msg=ls_msg+" "+ls[li_i]
next
messagebox("提示",ls_msg)
------解决方案--------------------
ls_string=ls_spbm+','+ls_tradetime+','+ls_lsj+','+ls_sl
还有一个简单的，以上语句先写成：
ls_string=ls_spbm+','+ls_tradetime+'.'+ls_lsj+';'+ls_sl
取值后，把"."";"替换回去就行了。