正则婚配嵌套div ,求PHP实现 _PHP

正则匹配嵌套div ,求PHP实现~
如下html串:
$str = '<div class="am1">
    <div class="image">1111111111</div>
    <div class="image">2222222222</div>
    <a href="test.php">link1</a>
</div>
<div class="am1">
     <div class="image">1111111111</div>
     <img src="./tt.gif" />
     <div class="image">2222222222</div>
</div>';
需要匹配出的结果:
    将<div class="am1">中的内容匹配出来, 即:
   1=>
           <div class="image">1111111111</div>
           <div class="image">2222222222</div>
           <a href="test.php">link1</a>

   2=>
           <div class="image">1111111111</div>
           <img src="./tt.gif" />
           <div class="image">2222222222</div>
php程序实现,在线等~

------解决方案--------------------

引用:

$patten='/(<div class="am1">(*)</div>)/';
preg_match_all($patten,$str,$match);

没有这么简单.因为会有多个</div>,你应该从内层开始查找,然后一层一层的往外,知道匹配到<div class="am1"></div>为止
------解决方案--------------------

<?php

$str = '<div class="am1">

    <div class="image">1111111111</div>

    <div class="image">2222222222</div>

    <a href="test.php">link1</a>

</div>

<div class="am1">

     <div class="image">1111111111</div>

     <img src="./tt.gif" />

     <div class="image">2222222222</div>

</div>';

if (preg_match_all('#<div[^>]*>((?>[^</div>]+
------解决方案--------------------
<a.+?>.+?</a>
------解决方案--------------------
<img.+?/>
------解决方案--------------------
(?R))*)</div>#is', $str, $matches)){

	print_r($matches);

}

 ?>