(
[0] => Array
(
[ak] => 1
[fs] => 12
[tss] => sd第三方f
)
[1] => Array
(
[ak] => 2
[fs] => 12
[tss] => 是的发生
)
[2] => Array
(
[ak] => 3
[fs] => 22
[tss] => 好新玩
)
[3] => Array
(
[ak] => 4
[fs] => 22
[tss] => 八实得分
)
[4] => Array
(
[ak] => 6
[fs] => 22
[tss] => 八实得分
)
)
上面的数组是$abc
我下奶想形成新的数组把fs的值作为键名，然后把fs的值相同的，形成新的数组，。。
数组如下：
(
[12] => Array
(
[0] => Array
(
[ak] => 2
[tss] => 是的发生
)
[1] => Array
(
[ak] => 2
[tss] => 是的发生
)
)
[22] => Array
(
...............
)
)
------解决思路----------------------
$ar = array (
array (
'ak' => '1',
'fs' => '12',
'tss' => 'sd第三方f',
),
array (
'ak' => '2',
'fs' => '12',
'tss' => '是的发生',
),
array (
'ak' => '3',
'fs' => '22',
'tss' => '好新玩',
),
array (
'ak' => '4',
'fs' => '22',
'tss' => '八实得分',
),
array (
'ak' => '6',
'fs' => '22',
'tss' => '八实得分',
),
);
$res = array();
foreach($ar as $r) {
$t = $r['fs'];
unset($r['fs']);
$res[$t][] = $r;
}
print_r($res);
Array
(
[12] => Array
(
[0] => Array
(
[ak] => 1
[tss] => sd第三方f
)
[1] => Array
(
[ak] => 2
[tss] => 是的发生
)
)
[22] => Array
(
[0] => Array
(
[ak] => 3
[tss] => 好新玩
)
[1] => Array
(
[ak] => 4
[tss] => 八实得分
)
[2] => Array
(
[ak] => 6
[tss] => 八实得分
)
)
)