将邮箱地址的第3 位到'@'之间的字符串替换为符号'*' 谢谢
------解决方案--------------------
echo preg_replace('/(?<=.{3}).+@/', '*@', [email protected]');[email protected]------解决方案--------------------
$str ="[email protected]";
$sub = substr($str, 2,strpos($str,'@') -2);
$len = strlen($sub);
$replaceStr = str_repeat('*',$len);
$newStr = str_replace($sub, $replaceStr, $str);
var_dump($newStr);