<li>
<ul>
<li><img src="images/small_case_1.jpg" alt=""/></li>
<li><img src="images/small_case_1.jpg" alt=""/></li>
<li><img src="images/small_case_1.jpg" alt=""/></li>
</ul>
</li>
<li>
<ul>
<li><img src="images/small_case_1.jpg" alt=""/></li>
<li><img src="images/small_case_1.jpg" alt=""/></li>
<li><img src="images/small_case_1.jpg" alt=""/></li>
</ul>
</li>
<li>
<ul>
<li><img src="images/small_case_1.jpg" alt=""/></li>
<li><img src="images/small_case_1.jpg" alt=""/></li>
<li><img src="images/small_case_1.jpg" alt=""/></li>
</ul>
</li>
上边的形式该怎么循环,新手求救。。。。
------解决方案--------------------
$arr = array(
'images/small_case_1.jpg',
'images/small_case_2.jpg',
'images/small_case_3.jpg',
'images/small_case_4.jpg',
'images/small_case_5.jpg',
'images/small_case_6.jpg',
'images/small_case_7.jpg',
'images/small_case_8.jpg',
'images/small_case_9.jpg'
);
function arr2li($arr){
$html = '';
if(is_array($arr) && !empty($arr)){
$count = count($arr);
for($i=0; $i<$count; $i++){
$rem = $i%3;
$html .= ($i!=0 && $rem==0) ? "</ul>\n\r</li>\n\r" : "";
$html .= ($rem==0) ? "<li>\n\r<ul>\n\r" : "";
$html .= sprintf("<li><img src=\"%s\"/></li>\n\r", $arr[$i]);
$html .= ($i+1==$count) ? "</ul>\n\r</li>" : "";
}
}
return $html;
}
/*
<li>
<ul>
<li><img src="images/small_case_1.jpg"/></li>
<li><img src="images/small_case_2.jpg"/></li>
<li><img src="images/small_case_3.jpg"/></li>
</ul>
</li>
<li>
<ul>
<li><img src="images/small_case_4.jpg"/></li>
<li><img src="images/small_case_5.jpg"/></li>
<li><img src="images/small_case_6.jpg"/></li>
</ul>
</li>
<li>
<ul>
<li><img src="images/small_case_7.jpg"/></li>
<li><img src="images/small_case_8.jpg"/></li>
<li><img src="images/small_case_9.jpg"/></li>
</ul>
</li>
*/
echo arr2li($arr);
------解决方案--------------------
$result=mysql_query("select * from case_list");
while($row=mysql_fetch_assoc($result)){
$ar[]=$row;
}
foreach(array_chunk($ar,3) as $v){
echo "<li>\n<ul>\n";
foreach($v as $vl) echo "<li><img src='{$vl['cl_pic']}' alt=''/></li>\n";
echo "</ul>\n</li>\n";
}