求解，getjson函数哪里写错了解决方法_PHP

求解，getjson函数哪里写错了
<script src="jquery-1.7.2.min.js" type="text/javascript"></script>
<script>
$(function(){
$.getjson("http://rate.taobao.com/member_rate.htm?content=1&result=0&from=rate&user_id=281461646&identity=1&rater=0&direction=0&timeLine=-7&callback=shop_rate_list", function(json){
alert("JSON Data: " + json);
});
})

弹不出获取的代码，求哪里写错了

------解决方案--------------------
而且，js中的json只是轻量级的数组，类似：

JScript code

var o={"xlid":"cxh","xldigitid":123456,"topscore":2000,"topplaytime":"2009-08-20"}；var jsonranklist=[{"xlid":"cxh","xldigitid":123456,"topscore":2000,"topplaytime":"2009-08-20"},{"xlid":"zd","xldigitid":123456,"topscore":1500,"topplaytime":"2009-11-20"}];
------解决方案--------------------
参考#2,而且你的json数据还封装在函数shop_rate_list()中，这就搞不懂了。去JavaScript区问问吧