从python中的列表列表中提取插槽

我还假设您希望： (a) 合并连续约会（即在前一个约会结束后立即开始约会） (b) 以上述方式格式化这些约会 (c) 在扁平列表中按天分组。

如果是这样，您可以使用以下方法解决此问题：

(a) 制作一个辅助函数，将您的天、小时和分钟变量转换为分钟：

def get_minute_val(day_val,hour_val,min_val):
    return (24*60*day_val)+(60*hour_val)+min_val

(b) 制作一个函数，接受两个约会，如果它们是连续的，要么将它们合并为一个，要么如果它们不连续则返回未合并的

def combine_if_consec(first,second):
    #Check whether appointments are consecutive
    if( get_minute_val(first[0],first[3],first[4]) + 1 == 
        get_minute_val(second[0],second[1],second[2])):
        #If so, return list containing combined appointment
        return [[first[0],first[1],first[2],second[3],second[4]]]
    else:
        #Else return uncombined appointments
        return [first,second]

(c) 在列表中的每个约会上迭代调用它，与最近添加的约会进行比较。 我有一个处理第一次约会的有点老套的方法。

def combine_all_appointments(app_list):
    #Add first appointment to app list
    output_list = [test[0]]

    #Loop through remaining appointments
    for next_app in app_list[1:]:
        #Remove most recent appointment to output list
        prev_app = output_list.pop()

        #Add either 2 combined appointments, or one single appointment to outputlist
        output_list += combine_if_overlap(prev_app,next_app)

    return output_list

(d) 做一个函数来做你想要的格式

def format_appointments(app_list):
    return [[x[0],'%d:%02d' % (x[1],x[2]),'%d:%02d' %(x[3],x[4])] for x in app_list]

(e) 和一个单独的按天分组约会，按天平展。

def group_by_day(app_list):
    output = {}
    #Loop through appointments
    for app in app_list:
        #Create new entry if day not yet in output dict
        if app[0] not in output:
            output[app[0]] = app[1:]
        #Add appointment values to relevant day
        else:
            output[app[0]] += app[1:]
    #Flatten dictionary
    return [[k, *output[k]] for k in output]

在您的输入上测试：

test = [[0, 4, 0, 4, 59],[0, 5, 0, 5, 59], [0, 6, 0, 6, 59], [0, 13, 0, 13, 59], [0, 14, 0, 14, 59], [0, 21, 0, 21, 59], [0, 22, 0, 22, 59], [1, 5, 0, 5, 59], [1, 6, 0, 6, 59], [1, 13, 0, 13, 59], [1, 14, 0, 14, 59], [1, 21, 0, 21, 59], [1, 22, 0, 22, 59], [2, 5, 0, 5, 59], [2, 6, 0, 6, 59], [2, 13, 0, 13, 59], [2, 14, 0, 14, 59], [2, 21, 0, 21, 59], [2, 22, 0, 22, 59], [3, 5, 0, 5, 59], [3, 6, 0, 6, 59], [3, 13, 0, 13, 59], [3, 14, 0, 14, 59], [3, 21, 0, 21, 59], [3, 22, 0, 22, 59], [4, 5, 0, 5, 59], [4, 6, 0, 6, 59], [4, 13, 0, 13, 59], [4, 14, 0, 14, 59], [4, 21, 0, 21, 59], [4, 22, 0, 22, 59], [5, 5, 0, 5, 59], [5, 6, 0, 6, 59], [5, 13, 0, 13, 59], [5, 14, 0, 14, 59], [5, 21, 0, 21, 59], [5, 22, 0, 22, 59], [6, 5, 0, 5, 59], [6, 6, 0, 6, 59], [6, 13, 0, 13, 59], [6, 14, 0, 14, 59], [6, 21, 0, 21, 59], [6, 22, 0, 22, 59]]

app_list = combine_all_appointments(test)
formatted = format_appointments(app_list)
grouped = group_by_day(formatted)

返回

[[0, '4:00', '6:59', '13:00', '14:59', '21:00', '22:59'], [1, '5:00', '6:59', '13:00', '14:59', '21:00', '22:59'], [2, '5:00', '6:59', '13:00', '14:59', '21:00', '22:59'], [3, '5:00', '6:59', '13:00', '14:59', '21:00', '22:59'], [4, '5:00', '6:59', '13:00', '14:59', '21:00', '22:59'], [5, '5:00', '6:59', '13:00', '14:59', '21:00', '22:59'], [6, '5:00', '6:59', '13:00', '14:59', '21:00', '22:59']]