问题描述
我正在处理一段。 我需要按字母顺序对文章中的单词进行排序，然后按相反的频率对其进行排序。 当我的单词计数功能对段落进行排序时，它也会对空白区域进行计数。 我做了一些修改，它仍然计算空字符串。 我想知道是否还有其他方法可以做到。 我的代码是：
def build_map( in_file, word_map ):
for line in in_file:
# Splits each line at blank space and turns it into
# a list.
word_list = line.split()
for word in word_list:
if word!='':
# Within the word_list, we are stripping empty space
# on both sides of each word and also stripping any
# punctuation on both side of each word in the list.
# Then, it turns each word to the lower case to avoid
# counting 'THE' and 'the' as two different words.
word = word.strip().strip(string.punctuation).lower()#program revised
add_word( word_map, word )
1楼
这应该使您朝着正确的方向前进，您可能需要通过删除句点和冒号来对其进行处理，并且无论如何都希望使其全部变为小写。
passage = '''I am dealing with a passage. I am required to sort the words in the passage alphabetically and then sort them by reverse frequency. When my word count function sorts the passage, it counts empty space too. I did some modification and it still counts the empty spaces. I am wondering if there is any other way to do it. My codes are:'''
words = set(passage.split())
alpha_sort = sorted(words, key=str.lower)
frequency_sort = sorted(words, key=passage.count, reverse=True)
2楼
要从字符串列表中过滤空字符串，我将使用：
my_list = filter(None, my_list)
3楼
也许您正在寻找
4楼
代替：
if word!='':
您应该使用：
if word.strip()!='':
因为第一个检查零长度的字符串，并且您要消除不是零长度的空格。 剥离仅空格字符串将使其长度为零。