当前位置: 代码迷 >> python >> 将字符串列表转换为元组列表
  详细解决方案

将字符串列表转换为元组列表

热度:57   发布时间:2023-07-16 11:01:04.0

我有一个字符串列表如下

['40799\t1890\t11-16-15\n', '40800\t1890\t11-17-15\n', '40801\t1890\t11-18-15\n', '40802\t1890\t11-19-15\n']

想要转换如下

 [('40799',1890,'11-16-15'), ('40800',1890,'11-17-15'), ('40801',1890,'11-18-15'), ('40802',1890,'11-19-15')]

Tab是每列的分隔符。 我能够使用一些循环转换。 但是想知道是否可以使用单个命令转换列表,因为列表可能包含很多项目

>>> data = ['40799\t1890\t11-16-15\n', '40800\t1890\t11-17-15\n', '40801\t1890\t11-18-15\n', '40802\t1890\t11-19-15\n']
>>> [(x, int(y), z) for x, y, z in (line.split() for line in data)]
[('40799', 1890, '11-16-15'), ('40800', 1890, '11-17-15'), ('40801', 1890, '11-18-15'), ('40802', 1890, '11-19-15')]
lst = ['40799\t1890\t11-16-15\n', '40800\t1890\t11-17-15\n', '40801\t1890\t11-18-15\n', '40802\t1890\t11-19-15\n']

print [tuple(s.split()) for s in lst]

输出:

[('40799', '1890', '11-16-15'), ('40800', '1890', '11-17-15'), ('40801', '1890', '11-18-15'), ('40802', '1890', '11-19-15')]
>>> data = ['40799\t1890\t11-16-15\n', '40800\t1890\t11-17-15\n', '40801\t1890\t11-18-15\n', '40802\t1890\t11-19-15\n']
>>> [tuple(line.split()) for line in data]
[('40799', '1890', '11-16-15'), ('40800', '1890', '11-17-15'), ('40801', '1890', '11-18-15'), ('40802', '1890', '11-19-15')]
  相关解决方案