alter proc p_qry
@TableName sysname, --表名
@纵轴 sysname, --交叉表最左面的列
@横轴 sysname, --交叉表最上面的列
@表体内容 sysname, --交叉表的数数据字段
@是否加横向合计 bit,--为1时在交叉表横向最右边加横向合计
@是否家纵向合计 bit --为1时在交叉表纵向最下边加纵向合计
as
declare @s nvarchar(4000),@sql varchar(8000)
--判断横向字段是否大于纵向字段数目,如果是,则交换纵横字段
set @s='declare @a sysname
if(select case when count(distinct ['+@纵轴+'])from ['+@TableName+'])=1
select @a=@纵轴,@纵轴=@横轴,@横轴=@a'
exec sp_executesql @s
,N'@纵轴 sysname out,@横轴 sysname out'
,@纵轴 out,@横轴 out
--生成交叉表处理语句
set @s='
set @s=''''
select @s=@s+'',[''+cast(['+@横轴+'] as varchar)+'']=sum(case ['+@横轴
+'] when ''''''+cast(['+@横轴+'] as varchar)+'''''' then ['+@表体内容+'] else 0 end)''
from ['+@TableName+']
group by ['+@横轴+']'
exec sp_executesql @s
,N'@s varchar(8000) out'
,@sql out
--是否生成合计字段的处理
declare @sum1 varchar(200),@sum2 varchar(200),@sum3 varchar(200)
select @sum1=case @是否加横向合计
when 1 then ',[合计]=sum(['+@表体内容+'])'
else '' end
,@sum2=case @是否家纵向合计
when 1 then '['+@纵轴+']=case grouping(['
+@纵轴+']) when 1 then ''合计'' else cast(['
+@纵轴+'] as varchar) end'
else '['+@纵轴+']' end
,@sum3=case @是否家纵向合计
when 1 then ' with rollup'
else '' end
--生成交叉表
exec('select '+@sum2+@sql+@sum1+'
from ['+@TableName+']
group by ['+@纵轴+']'+@sum3)
go
消息 156,级别 15,状态 1,第 2 行
关键字 'from' 附近有语法错误。
------解决思路----------------------
if(select case when count(distinct ['+@纵轴+'])from ['+@TableName+'])=1
------解决思路----------------------
你的语句什么意图自己知道啊!别人怎么知道该改成什么样子。
------解决思路----------------------
你的case when不完整,去掉case when,你可以这样修改。
--判断横向字段是否大于纵向字段数目,如果是,则交换纵横字段
SET @s='declare @a sysname
if(select count(distinct ['+@纵轴+']) from ['+@TableName+']) < (select count(distinct ['+@横轴+']) from ['+@TableName+'])
select @a=@纵轴,@纵轴=@横轴,@横轴=@a
'
------解决思路----------------------
if(select count(distinct ['+@纵轴+'])from ['+@TableName+'])=1