问题是这样的( 表一 如下 ):
id ip user time mac
1 1.1.1.1 a 2015-6-6 0000-1111-2222-3333
1 1.1.1.1 a 2015-6-6 9999-0000-4444-5555
1 2.2.2.2 a 2015-6-6 7777-1111-2222-66666
1 2.2.2.2 a 2015-6-6 8888-99999-2222-00000
表二 数据如下:
id ip time pv
1 1.1.1.1 2015-6-6 123
2 2.2.2.2 2015-6-6 456
通过第一表ip去重复后sql是这样写的:
select ip,count(*) as macs from 表一 where user='a' and time=' 时间 ' group by ip ORDER BY macs desc
但是现在想调出表二里面对应的IP相同日期的 PV 数 该如何写呢,麻烦指点 谢谢
------解决思路----------------------
select T1.ip,count(*) as macs,T2.pv
from 表一 T1
JOIN 表二 T2 ON T1.ip=T2.ip AND T1.[time]=T2.[time]
where user='a' and time=' 时间 '
group by T1.ip,T2.pv
ORDER BY macs desc
------解决思路----------------------
select T1.ip,count(*) as macs,T2.pv
from 表一 T1
JOIN 表二 T2 ON T1.ip=T2.ip AND T1.[time]=T2.[time]
where T1.[user]='a' and T2.[time]='2015-6-6'
group by T1.ip,T2.pv
ORDER BY macs desc