比如是: 1,,,,,1212,,,
要得出1212 怎么办呢?
------解决思路----------------------
Declare @SS NVarchar(100)
Set @SS = N'1,,,,,1212,,,'
Declare @Step Int
Set @Step = 1
--循环将第五个逗号前的数据截断
While @Step <=5
Begin
Set @SS = SUBSTRING(@SS,CHARINDEX(N',',@SS,1) + 1,LEN(@SS))
Set @Step = @Step + 1
End
--获取第6个逗号前的数据
Set @SS = SUBSTRING(@SS,1,CHARINDEX(N',',@SS,1) -1)
Print @ss
------解决思路----------------------
Create function char_index(@string varchar(8000),@char varchar(10),@index int)
--@string:待查找字符串,@index:查找位置
returns int
as
begin
declare
@i int,--当前找到第@i个
@position int--所在位置
set @position=1;
set @i=0;
while charindex(@char,@string,@position)>0
begin
set @position=charindex(@char,@string,@position)+1;
set @i=@i+1;
if @i=@index
begin
return @position-1;
end
end
return 0;--0表示未找到
end
select substring('sdf_dsf_dfgdg_ertr_erte',dbo.char_index('sdf_dsf_dfgdg_ertr_erte','f_',1)+len('f_'),
dbo.char_index('sdf_dsf_dfgdg_ertr_erte','f_',2)-len('f_')-dbo.char_index('sdf_dsf_dfgdg_ertr_erte','f_',1))