表格
time, no, price
11:00, a, 10
12:00, a, 11
13:00, a, 9
05:00, b, 20
06:00, b, 21
12:00, b, 22
有无高效的办法,获得相同NO，最高time的PRICE,
结果
time, no, price
13:00, a, 9
12:00, b, 22
------解决方案--------------------
with tb(time,no,price) as (
select '11:00', 'a', 10 union all
select '12:00', 'a', 11 union all
select '13:00', 'a', 9 union all
select '05:00', 'b', 20 union all
select '06:00', 'b', 21 union all
select '12:00', 'b', 22)
select * from tb a where not exists (select 1 from tb where no=a.no and a.time<time)
------解决方案--------------------
Select
*
from tb As a
Where time=(Select Max(time) from tb As x
Where x.no=a.no
)