有一个表 DATE ID CHANGE AMOUNT
2010 1 100 1000
2010 1 -200 1000
2010 1 200 1000
2011 1 200 1100
2011 1 400 1100
现在的AMOUNT 是 不动的余额。
我想让它 加入CHANGE 的变化做出下面的效果
DATE ID CHANGE AMOUNT
2010 1 100 1100
2010 1 -200 900
2010 1 200 1100
2011 1 200 1300
2011 1 400 1700
如何做 ?
------解决方案--------------------
- SQL code
declare @test table(DATE int, ID int, CHANGE int, AMOUNT int)insert into @testselect 2010, 1, 100, 1000 union allselect 2010, 1, -200, 1000 union allselect 2010, 1, 200, 1000 union allselect 2011, 1, 200, 1100 union allselect 2011, 1, 400, 1100;with cte as( select row_number() over(partition by ID order by getdate()) rn,* from @test)select DATE,ID,CHANGE,AMOUT=(select sum(CHANGE) from cte where t.ID=ID and t.rn>=rn)+1000 from cte t/*DATE ID CHANGE AMOUT----------- ----------- ----------- -----------2010 1 100 11002010 1 -200 9002010 1 200 11002011 1 200 13002011 1 400 1700*/
------解决方案--------------------
- SQL code
select date,id,change,amount+change as amount from tablename
------解决方案--------------------
- SQL code
--> 测试数据:[tb]IF OBJECT_ID('[tb]') IS NOT NULL DROP TABLE [tb]GO CREATE TABLE [tb]([DATE] INT,[ID] INT,[CHANGE] INT,[AMOUNT] INT)INSERT [tb]SELECT 2010,1,100,1000 UNION ALLSELECT 2010,1,-200,1000 UNION ALLSELECT 2010,1,200,1000 UNION ALLSELECT 2011,1,200,1100 UNION ALLSELECT 2011,1,400,1100--------------开始查询--------------------------;WITH cte AS (SELECT *, row_id=ROW_NUMBER()OVER(PARTITION BY [DATE] ORDER BY GETDATE()) FROM [tb])SELECT *,[AMOUNT]+(SELECT SUM([CHANGE]) FROM cte WHERE [DATE]=t.[DATE] AND row_id<=t.row_id) FROM cte AS t----------------结果----------------------------/* DATE ID CHANGE AMOUNT row_id (无列名)2010 1 100 1000 1 11002010 1 -200 1000 2 9002010 1 200 1000 3 11002011 1 200 1100 1 13002011 1 400 1100 2 1700*/--> 测试数据:[tb]IF OBJECT_ID('[tb]') IS NOT NULL DROP TABLE [tb]GO CREATE TABLE [tb]([DATE] INT,[ID] INT,[CHANGE] INT,[AMOUNT] INT)INSERT [tb]SELECT 2010,1,100,1000 UNION ALLSELECT 2010,1,-200,1000 UNION ALLSELECT 2010,1,200,1000 UNION ALLSELECT 2011,1,200,1100 UNION ALLSELECT 2011,1,400,1100--------------开始查询--------------------------;WITH cte AS (SELECT *, row_id=ROW_NUMBER()OVER(PARTITION BY [DATE] ORDER BY GETDATE()) FROM [tb])SELECT *,[AMOUNT]+(SELECT SUM([CHANGE]) FROM cte WHERE [DATE]=t.[DATE] AND row_id<=t.row_id) FROM cte AS t----------------结果----------------------------/* DATE ID CHANGE AMOUNT row_id (无列名)2010 1 100 1000 1 11002010 1 -200 1000 2 9002010 1 200 1000 3 11002011 1 200 1100 1 13002011 1 400 1100 2 1700*/