id jiquid date price
101 10101 2012-07-10 00:00:00.000 6.71
101 10101 2012-08-10 00:00:00.000 NULL
101 10101 2012-08-13 00:00:00.000 7.01
101 10101 2012-09-01 00:00:00.000 7.03
101 10101 2012-09-11 00:00:00.000 7.46
102 10201 2012-07-10 00:00:00.000 NULL
102 10201 2012-08-10 00:00:00.000 7.02
103 10315 2012-07-10 00:00:00.000 6.93
108 10801 2012-07-11 00:00:00.000 7.28
108 10801 2012-09-11 00:00:00.000 7.72
109 10901 2012-07-11 00:00:00.000 6.88
109 10901 2012-08-10 00:00:00.000 7.19
109 10901 2012-09-11 00:00:00.000 7.63
112 11201 2012-07-31 00:00:00.000 7.05
112 11201 2012-08-01 00:00:00.000 7.36
112 11201 2012-08-10 00:00:00.000 7.36
112 11201 2012-08-11 00:00:00.000 7.80
201 20101 2012-07-10 00:00:00.000 6.96
201 20101 2012-08-10 00:00:00.000 7.27
201 20101 2012-09-11 00:00:00.000 7.71
202 20201 2012-07-10 00:00:00.000 6.94
202 20201 2012-08-10 00:00:00.000 7.25
203 20301 2012-07-10 00:00:00.000 7.07
203 20301 2012-08-10 00:00:00.000 7.38
206 20601 2012-07-10 00:00:00.000 NULL
206 20601 2012-09-10 00:00:00.000 NULL
301 30101 2012-07-11 00:00:00.000 7.26
301 30101 2012-08-10 00:00:00.000 7.58
301 30101 2012-09-11 00:00:00.000 8.02
302 30201 2012-07-10 00:00:00.000 7.16
303 30301 2012-07-10 00:00:00.000 7.96
303 30301 2012-08-10 00:00:00.000 8.27
303 30301 2012-09-11 00:00:00.000 8.71
402 40201 2012-07-10 00:00:00.000 6.97
402 40201 2012-08-10 00:00:00.000 7.28
402 40201 2012-09-11 00:00:00.000 7.72
403 40301 2012-08-10 00:00:00.000 7.28
404 40401 2012-07-11 00:00:00.000 6.94
404 40401 2012-08-10 00:00:00.000 7.25
404 40401 2012-09-11 00:00:00.000 7.68
501 50101 2012-07-10 00:00:00.000 6.92
501 50101 2012-08-10 00:00:00.000 7.23
501 50101 2012-09-11 00:00:00.000 7.67
502 50201 2012-07-24 00:00:00.000 6.90
502 50201 2012-09-11 00:00:00.000 7.65
503 50301 2012-07-10 00:00:00.000 7.26
503 50301 2012-08-10 00:00:00.000 7.26
503 50301 2012-09-11 00:00:00.000 7.70
603 60301 2012-07-10 00:00:00.000 7.03
603 60301 2012-08-10 00:00:00.000 7.34
603 60301 2012-09-11 00:00:00.000 7.78
数据如上。
以id为分组，求出每个id中date最大的行
想了半天没想出来…
谢谢…
------解决方案--------------------
- SQL code
--1select * from tb as t where not exists(select 1 from tb where id=t.id and date>t.date)--2select * from tb as t where date(select max(date) from tb where id=t.id )--3select * from (select *,row_id=row_number() over(partition by id order by date desc) from tb) as t where row_id=1
------解决方案--------------------
- SQL code
--> --> (Roy)生成測試數據if not object_id('Tempdb..#T') is null drop table #TGoCreate table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))Insert #Tselect 1,N'A',N'A1' union allselect 2,N'A',N'A2' union allselect 3,N'A',N'A3' union allselect 4,N'B',N'B1' union allselect 5,N'B',N'B2'Go--Name相同ID最大的记录:方法1:Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID>a.ID)方法2:select a.* from #T a join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID order by ID方法3:select * from #T a where ID=(select max(ID) from #T where Name=a.Name) order by ID方法4:select a.* from #T a join #T b on a.Name=b.Name and a.ID<=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 方法5:select * from #T a group by ID,Name,Memo having ID=(select max(ID)from #T where Name=a.Name)方法6:select * from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)=0方法7:select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID desc)方法8:select * from #T a where ID!<all(select ID from #T where Name=a.Name)方法9(注:ID为唯一时可用):select * from #T a where ID in(select max(ID) from #T group by Name)--SQL2005:方法10:select ID,Name,Memo from (select *,max(ID)over(partition by Name) as MinID from #T a)T where ID=MinID方法11:select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID desc) as MinID from #T a)T where MinID=1生成结果2:/*ID Name Memo----------- ---- ----3 A A35 B B2(2 行受影响)*/