- SQL code
create table Goods(id int,name varchar(30),price int,sum int,sid int,creator varchar(20),createtime varchar(20),tid int)insert into Goods values('3','小碗熊','24','3','1','小明','2012年','3')drop table Supplierdrop table MyTypesdrop table Goodscreate table Supplier(sid int,name varchar(20),linkman varchar(20),tel varchar(20))insert into Supplier values('3','小明服饰','小张','13798542123')create table MyTypes(tid int,name varchar(20))insert into MyTypes values('3','饼干')select top 2 c.id,c.name,c.price,c.sum,c.creator,c.createtime,Supplier.linkman,Supplier.tel from Supplier,(select id,Goods.name,price,sum,sid,creator,createtime,MyTypes.name from Goods,MyTypes where MyTypes.tid=Goods.tid)as c where c.sid=Supplier.sid 查询出3张表的所有字段，现在问题是3张表都有name字段，但是名称不同，也就是说查询出来会出现3个name。怎么在查的过程中区别开来。
------解决方案--------------------
起一个别名，下面的
select top 2 c.id,c.NAME AS name1,Supplier.NAME AS NAME2,c.price,c.sum,c.creator,c.createtime,Supplier.linkman,Supplier.tel
from Supplier,
(select id,Goods.name,price,sum,sid,creator,createtime,MyTypes.name from Goods,MyTypes where MyTypes.tid=Goods.tid)as c
where c.sid=Supplier.sid
------解决方案--------------------
------解决方案--------------------
在select 后面的name列 加as 别名
- SQL code
select a.name as name1,b.name as name2 ...