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SQL查询过滤一个有关问题,会的请答一上

热度:41   发布时间:2016-04-27 11:18:49.0
SQL查询过滤一个问题,会的请答一下
;WITH ConfuseWords AS(
SELECT 'hi' AS [word_text],'meet' AS [relatedWord_Text], 1 as [LevelNo], 1 as [UnitNo]
UNION all
SELECT 'meet' as [word_text],'hi' AS [relatedWord_Text], 1 as [LevelNo], 1 as [UnitNo]
UNION all
SELECT 'he' as [word_text],'his' as [relatedWord_Text], 1 as [LevelNo], 3 as [UnitNo]
UNION all
SELECT 'his' as [word_text],'he' as [relatedWord_Text], 1 as [LevelNo], 3 as [UnitNo]
union all
SELECT 'table' as [word_text],'coffee table' as [relatedWord_Text], 1 as [LevelNo], 3 as [UnitNo]
)
select distinct cw1.* from ConfuseWords as cw1 
--结果如下:
--word_text relatedWord_Text LevelNo UnitNo
--hi meet 1 1
--meet hi 1 1
--he his 1 3
--his he 1 3

--想要输出结果如下:
--word_text relatedWord_Text LevelNo UnitNo
--hi meet 1 1
--he his 1 3




------解决方案--------------------
SQL code
;WITH ConfuseWords AS(SELECT 'hi' AS [word_text],'meet' AS [relatedWord_Text], 1 as [LevelNo], 1 as [UnitNo]UNION allSELECT 'meet' as [word_text],'hi' AS [relatedWord_Text], 1 as [LevelNo], 1 as [UnitNo]UNION allSELECT 'he' as [word_text],'his' as [relatedWord_Text], 1 as [LevelNo], 3 as [UnitNo]UNION allSELECT 'his' as [word_text],'he' as [relatedWord_Text], 1 as [LevelNo], 3 as [UnitNo] union allSELECT 'table' as [word_text],'coffee table' as [relatedWord_Text], 1 as [LevelNo], 3 as [UnitNo] ),cte as(    select row_number() over(order by word_text,relatedWord_Text) rn,* from ConfuseWords)select word_text,relatedWord_Text, LevelNo, UnitNo from cte twhere exists(select 1 from cte where t.word_text=relatedWord_Text and rn>t.rn)/*word_text relatedWord_Text LevelNo     UnitNo--------- ---------------- ----------- -----------he        his              1           3hi        meet             1           1*/
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