SQL 2000中文版
select
cast(substring(cast('一副接W头/PCS' as varbinary) + cast(space(40) as varbinary),1,40) as varchar(40)) f1,
datalength(
cast(substring(cast('一副接W头/PCS' as varbinary) + cast(space(40) as varbinary),1,40) as varchar(40))
) f2,
cast(substring(cast('一副接W头/PCS' as varbinary) + cast(space(40) as varbinary),41,40) as varchar(40)) f3,
datalength(
cast(substring(cast('一副接W头/PCS' as varbinary) + cast(space(40) as varbinary),41,40) as varchar(40))
) f4,
cast(substring(cast('一副接W头/PCS' as varbinary) + cast(space(40) as varbinary),81,40) as varchar(40)) f5,
datalength(
cast(substring(cast('一副接W头/PCS' as varbinary) + cast(space(40) as varbinary),81,40) as varchar(40))
) f6
f1 f2 f3 f4 f5 f6
-------------------------------------------------
一副接W头/PCS 40 3 0
(1 行受影响)
我想要的结果：
这个字段内的字符串 '一副接W头/PCS' 后不足长度补40个空格
f1 f2 f3 f4 f5 f6
-------------------------------------------------
一副接W头/PCS 40 40 40
有什么好方法解决吗？
------解决方案--------------------
- SQL code
select cast(substring(cast('一副接W头/PCS' as varbinary(400)) + cast(space(400) as varbinary(400)),1,40) as varchar(40)) f1,datalength(cast(substring(cast('一副接W头/PCS' as varbinary(400)) + cast(space(400) as varbinary(400)),1,40) as varchar(40))) f2, cast(substring(cast('一副接W头/PCS' as varbinary(400)) + cast(space(400) as varbinary(400)),41,40) as varchar(40)) f3,datalength(cast(substring(cast('一副接W头/PCS' as varbinary(400)) + cast(space(400) as varbinary(400)),41,40) as varchar(40))) f4,cast(substring(cast('一副接W头/PCS' as varbinary(400)) + cast(space(400) as varbinary(400)),81,40) as varchar(40)) f5,datalength(cast(substring(cast('一副接W头/PCS' as varbinary(400)) + cast(space(400) as varbinary(400)),81,40) as varchar(40))) f6-----------------f1 f2 f3 f4 f5 f6---------------------------------------- ----------- ---------------------------------------- ----------- ---------------------------------------- -----------一副接W头/PCS 40 40 40(1 行受影响)