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一个SQL查询解决思路

热度:21   发布时间:2016-04-27 11:19:41.0
一个SQL查询
数据表结构如下:CTable

 id name parent_id order_no
------------------------

  1 MS-SQL Server 0 1
  2 开发语言 0 2
  3 硬件/嵌入开发 0 3
  4 基础类 1 1
  5 应用实例 1 2
  6 VC/MFC 2 1
  7 VB 2 2
  8 汇编语言 3 1
  9 界面 6 1

怎么能用简单的SQL查询,不要用存储过程、创建临时表等,检索出如下效果  

id name parent_id order_no
------------------------

  1 MS-SQL Server 0 1
  4 基础类 1 1
  5 应用实例 1 2
  2 开发语言 0 2
  6 VC/MFC 2 1
  9 界面 6 1
  7 VB 2 2
  3 硬件/嵌入开发 0 3
  8 汇编语言 3 1

 

就是按照CSDN左侧菜单的显示顺序,菜单级数不定

------解决方案--------------------
SQL code
BOM按节点排序应用实例 ----------------------------------------  Author : htl258(Tony)--  Date   : 2010-04-23 02:37:28--  Version:Microsoft SQL Server 2008 (RTM) - 10.0.1600.22 (Intel X86) --          Jul  9 2008 14:43:34 --          Copyright (c) 1988-2008 Microsoft Corporation--          Developer Edition on Windows NT 5.1 <X86> (Build 2600: Service Pack 3)--  Subject: BOM按节点排序应用实例-------------------------------------- --实例1:--> 生成测试数据表:tb IF NOT OBJECT_ID('[tb]') IS NULL    DROP TABLE [tb]GOCREATE TABLE [tb]([id] INT,[code] NVARCHAR(10),[pid] INT,[name] NVARCHAR(10))INSERT [tb]SELECT 1,'01',0,N'服装' UNION ALLSELECT 2,'01',1,N'男装' UNION ALLSELECT 3,'01',2,N'西装' UNION ALLSELECT 4,'01',3,N'全毛' UNION ALLSELECT 5,'02',3,N'化纤' UNION ALLSELECT 6,'02',2,N'休闲装' UNION ALLSELECT 7,'02',1,N'女装' UNION ALLSELECT 8,'01',7,N'套装' UNION ALLSELECT 9,'02',7,N'职业装' UNION ALLSELECT 10,'03',7,N'休闲装' UNION ALLSELECT 11,'04',7,N'西装' UNION ALLSELECT 12,'01',11,N'全毛' UNION ALLSELECT 13,'02',11,N'化纤' UNION ALLSELECT 14,'05',7,N'休闲装'GO--SELECT * FROM [tb] -->SQL查询如下: ;WITH T AS(    SELECT CAST(CODE AS VARCHAR(20)) AS CODE,*,        CAST(ID AS VARBINARY(MAX)) AS px     FROM tb AS A    WHERE NOT EXISTS(SELECT * FROM tb WHERE id=A.pid)    UNION ALL     SELECT CAST(B.CODE+A.CODE AS VARCHAR(20)),A.*,         CAST(B.px+CAST(A.ID AS VARBINARY) AS VARBINARY(MAX))        FROM tb AS A        JOIN T AS B           ON A.pid=B.id)SELECT Code,Name FROM T ORDER BY px/*Code                 Name-------------------- ----------01                   服装0101                 男装010101               西装01010101             全毛01010102             化纤010102               休闲装0102                 女装010201               套装010202               职业装010203               休闲装010204               西装01020401             全毛01020402             化纤010205               休闲装 (14 行受影响)*/ --实例2:--> 生成测试数据表:tbIF NOT OBJECT_ID('[tb]') IS NULL    DROP TABLE [tb]GOCREATE TABLE [tb]([id] INT,[parentid] INT,[categoryname] NVARCHAR(10))INSERT [tb]SELECT 1,0,'test1' UNION ALLSELECT 2,0,'test2' UNION ALLSELECT 3,1,'test1.1' UNION ALLSELECT 4,2,'test2.1' UNION ALLSELECT 5,3,'test1.1.1' UNION ALLSELECT 6,1,'test1.2'GO--SELECT * FROM [tb]-->SQL查询如下:;WITH T AS(    SELECT *,CAST(ID AS VARBINARY(MAX)) AS px     FROM tb AS A    WHERE NOT EXISTS(SELECT * FROM tb WHERE id=A.[parentid])    UNION ALL     SELECT A.*,CAST(B.px+CAST(A.ID AS VARBINARY) AS VARBINARY(MAX))      FROM tb AS A        JOIN T AS B           ON A.[parentid]=B.id)SELECT [id],[parentid],[categoryname] FROM T ORDER BY px/*id          parentid    categoryname----------- ----------- ------------1           0           test13           1           test1.15           3           test1.1.16           1           test1.22           0           test24           2           test2.1(6 行受影响)*/本文来自CSDN博客,转载请标明出处:http://blog.csdn.net/htl258/archive/2010/04/23/5518166.aspx
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