怎么将B表的一个字段的数据复制到A表中的一个字段，这个字段名一样的

--新建#aselect *into #afrom (select 1 a ,'a' b union allselect 2 ,'b' union allselect 3 ,'c' union allselect 4 ,'d' )a--新建#bselect *into #bfrom (select 5 a ,'a' b union allselect 6 ,'b' union allselect 7 ,'c' union allselect 8 ,'d' )a--查询#aselect * from #a--result:a           b----------- ----1           a2           b3           c4           d(4 行受影响)--查询#bselect * from #b--result:a           b----------- ----5           a6           b7           c8           d(4 行受影响)--插入#a中a字段insert into #a select a,'' b from #b(4 行受影响)--查询表#aselect * from #a--result:a           b----------- ----5           6           7           8           1           a2           b3           c4           d(8 行受影响)
------解决方案--------------------
insert b (column1) select column1 from a
------解决方案--------------------
SQL code
INSERT INTO TB_A(COLUMN_NAME)SELECT COLUMN_NAME FROM TB_B