现在有两个表A,B,
A表:
ID NAME
1 amy
2 wang
3 chris
B表
ID PRICE LOCATION
1 11 aaa
1 22 bbb
2 10 ccc
2 15 eee
B表中最多有两条A.ID=B.ID的数据,我想得到的查询结果为:
ID NAME RESULT1 RESULT2
1 amy 11|aaa 22|bbb
2 wang 10|ccc 15|eee
请问查询语句如果写,多谢各位。
------解决方案--------------------
- SQL code
;with cte as (select ID,NAME,[RESULT1]=stuff((select '|'+[RESULT1] from B t where ID=tb.ID for xml path('')), 1, 1, '')) from tb group by id )a,union all(select ID,NAME,[RESULT2]=stuff((select '|'+[RESULT2] from B t where ID=tb.ID for xml path('')), 1, 1, '')) from tb group by id )bselect ID,NAME,RESULT1,RESULT2 from cte left join A on cte.ID=A.id
------解决方案--------------------
- SQL code
--> 测试数据:[ta]IF OBJECT_ID('[ta]') IS NOT NULL DROP TABLE [ta]GOCREATE TABLE [ta]([ID] INT,[NAME] VARCHAR(5))INSERT [ta]SELECT 1,'amy' UNION ALLSELECT 2,'wang' UNION ALLSELECT 3,'chris'GOIF OBJECT_ID('[tb]') IS NOT NULL DROP TABLE [tb]GOCREATE TABLE [tb]([ID] INT,[PRICE] INT,[LOCATION] VARCHAR(3))INSERT [tb]SELECT 1,11,'aaa' UNION ALLSELECT 1,22,'bbb' UNION ALLSELECT 2,10,'ccc' UNION ALLSELECT 2,15,'eee'GO--> 测试语句:SELECT a.[ID],a.[name],max(case when b.row_id=1 then ltrim([PRICE])+'|'+[LOCATION] else '' end) as [result1],max(case when b.row_id=2 then ltrim([PRICE])+'|'+[LOCATION] else '' end) as [result2]FROM [ta] a,(select *,row_id=row_number() over(partition by id order by id) from tb) as b where a.[ID]=b.[ID]group by a.[ID],a.[name]/*ID name result1 result2----------- ----- ---------------- ----------------1 amy 11|aaa 22|bbb2 wang 10|ccc 15|eee*/