SQL数据库查询有关问题！

 表1：    <table>     <tr>      <td>Name</td>      <td>数量</td>     </tr>     <tr>      <td>A</td>      <td>100</td>     </tr>     <tr>      <td>B</td>      <td>200</td>     </tr>     <tr>      <td>A</td>      <td>150</td>     </tr>     <tr>      <td>A</td>      <td>100</td>     </tr>     <tr>      <td>B</td>      <td>300</td>     </tr>    </table>    <br />    表2：    <table>     <tr>      <td>Name</td>      <td>单价</td>     </tr>     <tr>      <td>A</td>      <td>0.2</td>     </tr>     <tr>      <td>B</td>      <td>0.6</td>     </tr>    </table>    <br />    查询结果：    <table>     <tr>      <td>Name</td>      <td>数量</td>      <td>总价</td>     </tr>     <tr>      <td>A</td>      <td>3</td>      <td>70</td>     </tr>     <tr>      <td>B</td>      <td>2</td>      <td>300</td>     </tr>    </table>

select     a.name,    sum(a.数量)*b.单价 as 合计 from     tb1 ainner join    tb2 bon     a.name=b.namegroup by     a.name
------解决方案--------------------
SQL code
create table #A(    name nvarchar(10),    number int)insert into #Aselect 'A', 100insert into #Aselect 'B', 200unionselect 'A', 150unionselect 'A', 100unionselect 'B', 300create table #B(    name nvarchar(10),    price decimal(5, 1))insert into #Bselect 'A', 0.2unionselect 'B', 0.6--Query--select a.name, count(*) as number, sum(a.number * b.price) as totPricefrom #A a, #B bwhere a.name = b.namegroup by a.nameorder by a.name--name    number    totPrice--A    3    70.0--B    2    300.0