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焦急请大神帮忙~

热度:84   发布时间:2016-04-27 11:59:58.0
着急,请大神帮忙~急~~~~~~~~~~~~~~~~~~~~~~
现在有两张表 
A表 
ksdm zje
01 100
02 200
03 250

B表
ksdm zje
02 150
03 100
04 500

怎么得到表
ksdm zje 
01 100
02 350
03 350
04 500


------解决方案--------------------
SQL code
------------------------------ Author  :fredrickhu(小F,向高手学习)-- Date    :2012-07-11 10:55:48-- Version:--      Microsoft SQL Server 2008 R2 (RTM) - 10.50.1617.0 (Intel X86) --    Apr 22 2011 11:57:00 --    Copyright (c) Microsoft Corporation--    Enterprise Edition on Windows NT 6.1 <X64> (Build 7600: ) (WOW64)--------------------------------> 测试数据:[A]if object_id('[A]') is not null drop table [A]go create table [A]([ksdm] varchar(2),[zje] int)insert [A]select '01',100 union allselect '02',200 union allselect '03',250--> 测试数据:[b]if object_id('[b]') is not null drop table [b]go create table [b]([ksdm] varchar(2),[zje] int)insert [b]select '02',150 union allselect '03',100 union allselect '04',500--------------开始查询--------------------------select ksdm,sum(zje) as zje from (select * from A union all select * from b)tgroup by  ksdm----------------结果----------------------------/* ksdm zje---- -----------01   10002   35003   35004   500(4 行受影响)*/
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