一遇到递归就头大, 这个如何效率解决

id    name    pid3    c    14    d    15    e    26    f    47    g    38    h    69    i    710    j    711    k    512    l    913    m    1014    n    815    o    14

id    root4    17    19    111    212    115    1

;with t(id,pid,topid)as(select id,pid,pid     from A     where not exists (select 1 from A A1 where A.pid=A1.id)union allselect A.id,A.pid,t.topid    from A,t    where A.pid=t.id)select B.id,t.topid [root] from B,t where B.id=t.id;