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复杂的sql语句如何写

热度:68   发布时间:2016-04-27 12:12:08.0
求一个复杂的sql语句怎么写?
有数据表 a

字段 name a b c d

  001 1 2 3 4  
  001 5 6 7 4
  001 2 3 4 8
  002 1 2 3 4
  002 3 2 2 5
  003 2 2 2 4

问题:根据name 求出 a,b,c 三列的平均值?并且,再根据 name 求出 d 列里,小于等于4的个数比例和大于4个数的比例,每一个不同的name都要算。最好能放在一个表里!!
例如: name a平均 b平均 c平均 d小、等于deng4 d大于4
  001 2.66 3.66 4.66 66% 33%
  002 2 2 2.5 50% 50%
  003 2 2 2 100% 0
最后,最好有个统计,就是所有的平均值和比例
比如: 总计 2.22 2.55 3.03 66% 33%
 

------解决方案--------------------
SQL code
SELECT NAME,AVG(A) AS A,AVG(B) AS B,AVG(C) AS C,SUM(CASE WHEN D<=4 THEN 1 ELSE 0 END)*100.0/SUM(1) AS [<=4],SUM(CASE WHEN >4 THEN 1 ELSE 0 END)*100.0/SUM(1) AS [>4]FROM AGROUP BY NAMEUNION ALLSELECT NAME = '总计',AVG(A) AS A,AVG(B) AS B,AVG(C) AS C,SUM(CASE WHEN D<=4 THEN 1 ELSE 0 END)*100.0/SUM(1) AS [<=4],SUM(CASE WHEN >4 THEN 1 ELSE 0 END)*100.0/SUM(1) AS [>4]FROM A
------解决方案--------------------
SQL code
--> 测试数据:[ta]IF OBJECT_ID('[ta]') IS NOT NULL DROP TABLE [ta]GO CREATE TABLE [ta]([name] VARCHAR(3),[a] INT,[b] INT,[c] INT,[d] INT)INSERT [ta]SELECT '001',1,2,3,4 UNION ALLSELECT '001',5,6,7,4 UNION ALLSELECT '001',2,3,4,8 UNION ALLSELECT '002',1,2,3,4 UNION ALLSELECT '002',3,2,2,5 UNION ALLSELECT '003',2,2,2,4--------------开始查询--------------------------SELECT  [name], AVG([a] * 1.0), AVG([b] * 1.0), AVG([c] * 1.0), SUM(CASE WHEN [d]<=4 THEN 1 ELSE 0 END) * 100.0 / COUNT([name])FROM    [ta]GROUP BY [name]WITH ROLLUP  ----------------结果----------------------------/* name                                                                                                                         ---- --------------------------------------- --------------------------------------- --------------------------------------- ---------------------------------------001  2.666666                                3.666666                                4.666666                                66.666666666666002  2.000000                                2.000000                                2.500000                                50.000000000000003  2.000000                                2.000000                                2.000000                                100.000000000000NULL 2.333333                                2.833333                                3.500000                                66.666666666666(4 行受影响)*/
------解决方案--------------------
SQL code
--> 测试数据:[ta]IF OBJECT_ID('[ta]') IS NOT NULL DROP TABLE [ta]GO CREATE TABLE [ta]([name] VARCHAR(3),[a] INT,[b] INT,[c] INT,[d] INT)INSERT [ta]SELECT '001',1,2,3,4 UNION ALLSELECT '001',5,6,7,4 UNION ALLSELECT '001',2,3,4,8 UNION ALLSELECT '002',1,2,3,4 UNION ALLSELECT '002',3,2,2,5 UNION ALLSELECT '003',2,2,2,4--------------开始查询--------------------------SELECT  [name], AVG([a] * 1.0), AVG([b] * 1.0), AVG([c] * 1.0), SUM(CASE WHEN [d]<=4 THEN 1 ELSE 0 END) * 100.0 / COUNT([name])FROM    [ta]GROUP BY [name]UNION ALL SELECT  '统计', AVG([a] * 1.0), AVG([b] * 1.0), AVG([c] * 1.0), SUM(CASE WHEN [d]<=4 THEN 1 ELSE 0 END) * 100.0 / COUNT([name])FROM    [ta]----------------结果----------------------------/* name                                                                                                                         ---- --------------------------------------- --------------------------------------- --------------------------------------- ---------------------------------------001  2.666666                                3.666666                                4.666666                                66.666666666666002  2.000000                                2.000000                                2.500000                                50.000000000000003  2.000000                                2.000000                                2.000000                                100.000000000000统计   2.333333                                2.833333                                3.500000                                66.666666666666(4 行受影响)*/
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