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sql语句求连续盈亏的天数解决方法

热度:109   发布时间:2016-04-27 13:13:12.0
sql语句求连续盈亏的天数


加入要根据前面连个字段求出后面一个字段,怎么写程序?

------解决方案--------------------
SQL code
-- 建表create table ta(dt datetime, n int);insert into ta(dt, n)select '2112-1-1', -39  union allselect '2112-1-2', -8  union allselect '2112-1-3', 32  union allselect '2112-1-4', -3  union allselect '2112-1-5', -39  union allselect '2112-1-6', -32  union allselect '2112-1-7', 40  union allselect '2112-1-8', 20  union allselect '2112-1-9', -25-- 查询连续盈亏数;with t as(    select a.r, a.dt, a.n, a.d  from (        select r=row_number() over (order by dt asc), dt, n, d=case when n<0 then -1 else 1 end from ta     ) a where a.r=1    union all    select b.r, b.dt, b.n, d=case             when b.n<0 and t.d<0 then t.d-1             when b.n<0 and t.d>=0 then -1             when b.n>=0 and t.d<0 then 1            when b.n>=0 and t.d>=0 then t.d+1            end     from (        select r=row_number() over (order by dt asc), dt, n    from ta     ) b, t where b.r=t.r+1)select * from t
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