初学者有关问题，SQL2000合并数据

合并列值 --*******************************************************************************************表结构，数据如下： id    value ----- ------ 1    aa 1    bb 2    aaa 2    bbb 2    ccc 需要得到结果： id    values ------ ----------- 1      aa,bb 2      aaa,bbb,ccc 即：group by id, 求 value 的和（字符串相加） 1. 旧的解决方法(在sql server 2000中只能用函数解决。) --=============================================================================create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go --1. 创建处理函数 CREATE FUNCTION dbo.f_strUnite(@id int) RETURNS varchar(8000) AS BEGIN     DECLARE @str varchar(8000)     SET @str = ''     SELECT @str = @str + ',' + value FROM tb WHERE [email protected]     RETURN STUFF(@str, 1, 1, '') END GO -- 调用函数 SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id drop table tb drop function dbo.f_strUnite go/* id          value      ----------- ----------- 1          aa,bb 2          aaa,bbb,ccc （所影响的行数为 2 行） */ --===================================================================================2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go -- 查询处理 SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(         SELECT [values]= STUFF(REPLACE(REPLACE(             (                 SELECT value FROM tb N                 WHERE id = A.id                 FOR XML AUTO             ), ' <N value="', ','), '"/>', ''), 1, 1, '') )N drop table tb /* id          values ----------- ----------- 1          aa,bb 2          aaa,bbb,ccc (2 行受影响) */ --SQL2005中的方法2 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') from tb group by id /* id          values ----------- -------------------- 1          aa,bb 2          aaa,bbb,ccc (2 row(s) affected) */
------解决方案--------------------
SQL code
------------------------------ Author  :fredrickhu(小F，向高手学习)-- Date    :2011-11-21 13:58:33-- Version:--      Microsoft SQL Server 2008 R2 (RTM) - 10.50.1617.0 (Intel X86) --    Apr 22 2011 11:57:00 --    Copyright (c) Microsoft Corporation--    Enterprise Evaluation Edition on Windows NT 6.1 <X64> (Build 7600: ) (WOW64)--------------------------------> 测试数据：[tb]if object_id('[tb]') is not null drop table [tb]go create table [tb]([names] varchar(1),[masterid] int)insert [tb]select 'A',1 union allselect 'B',1 union allselect 'C',2 union allselect 'D',3--------------开始查询--------------------------if OBJECT_ID('dbo.f_strUnite') is not nulldrop FUNCTION dbo.f_strUnitegoCREATE FUNCTION dbo.f_strUnite(@id int) RETURNS varchar(8000) AS BEGIN     DECLARE @str varchar(8000)     SET @str = ''     SELECT @str = @str + ',' + ltrim(names) FROM tb WHERE [email protected]     RETURN STUFF(@str, 1, 1, '') END GO -- 调用函数 SELECt masterid, name = dbo.f_strUnite( masterid) FROM tb GROUP BY  masterid drop table tb drop function dbo.f_strUnite go----------------结果----------------------------/* masterid    name----------- ----------------------------------------------------------------------------------------------------------------1           A,B2           C3           D*/