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求sql语句.该如何解决

热度:16   发布时间:2016-04-27 17:59:11.0
求sql语句...
SQL code
create table [Table1]( [name] nvarchar(10),[time] datetime,[Class] nvarchar(10))INSERT INTO [Table1]([name],[time],[Class])VALUES('第一个','2011-10-24','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第一个','2011-10-24','B班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第二个','2011-10-24','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第二个','2011-10-24','B班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第三个','2011-10-24','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第五个','2011-10-24','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第四个','2011-10-23','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第五个','2011-10-23','B班')goselect * from Table1 -----执行结果如下:第一个    2011-10-24 00:00:00.000    A班第一个    2011-10-24 00:00:00.000    B班第二个    2011-10-24 00:00:00.000    A班第二个    2011-10-24 00:00:00.000    B班第三个    2011-10-24 00:00:00.000    A班第五个    2011-10-24 00:00:00.000    A班第四个    2011-10-23 00:00:00.000    A班第五个    2011-10-23 00:00:00.000    B班


SQL code
--想要得到的结果如下:第一个    2011-10-24 00:00:00.000    A班第一个    2011-10-24 00:00:00.000    B班第二个    2011-10-24 00:00:00.000    A班第二个    2011-10-24 00:00:00.000    B班第三个    2011-10-24 00:00:00.000    A班第三个    2011-10-24 00:00:00.000    B班 --添加第五个    2011-10-24 00:00:00.000    A班第五个    2011-10-24 00:00:00.000    B班 --添加第四个    2011-10-23 00:00:00.000    A班第四个    2011-10-23 00:00:00.000    B班 --添加第五个    2011-10-23 00:00:00.000    A班 --添加第五个    2011-10-23 00:00:00.000    B班 


结果贴出来,也就一目了然...



------解决方案--------------------
SQL code
select a.[name],a.[time],b.[Class]from (select distinct [name],[time]from table1) a cross join (select distinct [Class]from table1) b
------解决方案--------------------
SQL code
create table [Table1]( [name] nvarchar(10),[time] datetime,[Class] nvarchar(10))INSERT INTO [Table1]([name],[time],[Class])VALUES('第一个','2011-10-24','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第一个','2011-10-24','B班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第二个','2011-10-24','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第二个','2011-10-24','B班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第三个','2011-10-24','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第五个','2011-10-24','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第四个','2011-10-23','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第五个','2011-10-23','B班')goselect name,a.time,b.Class  from ((select distinct name,time from Table1)a cross join (select time,class from Table1)b  )where a.time=b.timegroup by  name,a.time,b.Class order by  CHARINDEX(name,'第一个第二个第三个第四个第五个')drop table Table1 /*name       time                    Class---------- ----------------------- ----------第一个        2011-10-24 00:00:00.000 A班第一个        2011-10-24 00:00:00.000 B班第二个        2011-10-24 00:00:00.000 A班第二个        2011-10-24 00:00:00.000 B班第三个        2011-10-24 00:00:00.000 A班第三个        2011-10-24 00:00:00.000 B班第四个        2011-10-23 00:00:00.000 A班第四个        2011-10-23 00:00:00.000 B班第五个        2011-10-23 00:00:00.000 A班第五个        2011-10-23 00:00:00.000 B班第五个        2011-10-24 00:00:00.000 A班第五个        2011-10-24 00:00:00.000 B班(12 行受影响)*/
------解决方案--------------------
SQL code
create table [Table1]( [name] nvarchar(10),[time] datetime,[Class] nvarchar(10))INSERT INTO [Table1]([name],[time],[Class])VALUES('第一个','2011-10-24','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第一个','2011-10-24','B班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第二个','2011-10-24','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第二个','2011-10-24','B班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第三个','2011-10-24','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第五个','2011-10-24','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第四个','2011-10-23','A班')INSERT INTO [Table1]([name],[time],[Class])VALUES('第五个','2011-10-23','B班')goinsert into [Table1]select * from (select distinct name,[time] from [Table1]) a,(select distinct [class] from [Table1]) bexceptselect * from [Table1]select * from [Table1] order by  CHARINDEX(name,'第一个第二个第三个第四个第五个')/*name       time                    Class---------- ----------------------- ----------第一个        2011-10-24 00:00:00.000 A班第一个        2011-10-24 00:00:00.000 B班第二个        2011-10-24 00:00:00.000 A班第二个        2011-10-24 00:00:00.000 B班第三个        2011-10-24 00:00:00.000 A班第三个        2011-10-24 00:00:00.000 B班第四个        2011-10-23 00:00:00.000 B班第四个        2011-10-23 00:00:00.000 A班第五个        2011-10-23 00:00:00.000 B班第五个        2011-10-23 00:00:00.000 A班第五个        2011-10-24 00:00:00.000 B班第五个        2011-10-24 00:00:00.000 A班(12 行受影响)
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