如何通过vba获取一个目录下的所有文件夹名称、大小、文件夹中所有文档数量？
例如：
vb-vba1
-1.txt
-2.txt
-vba2
-3.txt
-vba3
需要的结果是:
文件夹名称 文件夹大小 文件夹文档数量
vba1 2
vba2 1
vba3 0
------解决方案--------------------------------------------------------
<hta>
<head>
<META HTTP-EQUIV= "pragma " CONTENT= "no-cache ">
<META HTTP-EQUIV= "Cache-Control " CONTENT= "no-cache, must-revalidate ">
<META HTTP-EQUIV= "expires " CONTENT= "0 ">
<title> 命名程序 </title>
</head>
<body scroll= "auto " style= "border:none; color:green; " bgcolor=black topmargin=0 leftmargin=0 rightmargin=0 bottommargin=0 >
<textarea id=show rows=10 style= "width:100%; "> </textarea>
<textarea id=dofile rows=20 style= "width:100%; " title=请在这输入处理文件的方法> function (path){
请在这输入处理文件的方法,其它不变。
} </textarea>
源文件夹 <input id= "sourcefolder " type=file> <br> <input type=button value=获取全部文件夹 onclick= "getallfolder(sourcefolder.value) ">
<input type=button value=处理所有文件 onclick= "doallfile() ">
<input type=button value=清除 onclick= "showtxt( '已清除所有定时 '); clearTimeout(fsotime) ">
<SCRIPT language= "javascript ">
<!--
var fso = new ActiveXObject( "Scripting.FileSystemObject ");
var runtime = 1;
var foldersarray;
var fsotime;
var nowi;
var fp;
var theno;
var mydofile;
function showtxt(txt)
{
show.focus();
show.value += txt + "\n ";
}
function reportError(msg,url,line)
{
alert( "当前页的脚本发生错误: \n\n信息: " + msg + "\n\n行： " + line);
return true;
}
window.onerror = reportError;
function getallfolder(path)
{
if ( fso.folderExists(path) == false)
{
showtxt( "出错啦！\n[ " + path + "] 文件夹不存在! ");
return false;
}
if(fso.DriveExists(path))
{
path += "\\ ";
}
mygetfolder(path);
}
function mygetfolder(path){//自己递归时没参数
if(path != undefined)
{
clearTimeout(fsotime);
fp = null;
nowi = -1;
theno = 1;
foldersarray = new Array(fso.getFolder(path).path);
showtxt( "开始获取文件夹...\n " + (theno++) + ": " + fso.getFolder(path).path);
}
try
{
if(fp == null)