当前位置: 代码迷 >> Web前端 >> 是jqGrid "Array Data"例子有关问题
  详细解决方案

是jqGrid "Array Data"例子有关问题

热度:1022   发布时间:2012-11-25 11:44:31.0
是jqGrid "Array Data"例子问题?

今天在做jqGrid例子时,发现Array Data有个问题,写下来问问大家

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gbk" />
<title>jqGrid Demos</title>
<link rel="stylesheet" type="text/css" media="screen" href="themes/redmond/jquery-ui-1.7.1.custom.css" />
<link rel="stylesheet" type="text/css" media="screen" href="themes/ui.jqgrid.css" />
<link rel="stylesheet" type="text/css" media="screen" href="themes/ui.multiselect.css" />

<script src="js/jquery.js" type="text/javascript"></script>
<script src="js/jquery-ui-1.7.2.custom.min.js" type="text/javascript"></script>
<script src="js/jquery.layout.js" type="text/javascript"></script>
<script src="js/i18n/grid.locale-en.js" type="text/javascript"></script>
<script type="text/javascript">
	$.jgrid.no_legacy_api = true;
	$.jgrid.useJSON = true;
</script>
<script src="js/jquery.jqGrid.min.js" type="text/javascript"></script>
<script src="js/jquery.tablednd.js" type="text/javascript"></script>
<script src="js/jquery.contextmenu.js" type="text/javascript"></script>
<script src="js/ui.multiselect.js" type="text/javascript"></script>
<script type="text/javascript">   
jQuery(document).ready(function(){   
  jQuery("#list4").jqGrid({
    datatype: "local",
	height: 250,
   	colNames:['Inv No','Date', 'Client', 'Amount','Tax','Total','Notes'],
   	colModel:[
   		{name:'id',index:'id', width:60, sorttype:"int"},
   		{name:'invdate',index:'invdate', width:90, sorttype:"date"},
   		{name:'name',index:'name', width:100},
   		{name:'amount',index:'amount', width:80, align:"right",sorttype:"float"},
   		{name:'tax',index:'tax', width:80, align:"right",sorttype:"float"},		
   		{name:'total',index:'total', width:80,align:"right",sorttype:"float"},		
   		{name:'note',index:'note', width:150, sortable:false}		
   	],
   	multiselect: true,
   	caption: "Manipulating Array Data"
});
var mydata = [   
            {id:"1",invdate:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},   
            {id:"2",invdate:"2007-10-02",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},   
            {id:"3",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},   
            {id:"4",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},   
            {id:"5",invdate:"2007-10-05",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},   
            {id:"6",invdate:"2007-09-06",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},   
            {id:"7",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},   
            {id:"8",invdate:"2007-10-03",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},   
            {id:"9",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"}   
            ];   
    for(var i=0;i<=mydata.length;i++)   
           //jqgrid_demo35中用这个方法,发现不能加载数据
       //  jQuery("#list4").jqGrid('addRowData',i+1,mydata[i]);

	
           //我改用以下方法就可以成功加载,不知为什么?还请高手指点???
           jQuery("#list4").addRowData(i+1,mydata[i]);   

});   
</script>   
<body>   
<table id="list4"></table>
</body>
</html>

?

1 楼 zuozhengfeng 2010-02-03  
我两个都不行,更是不知道什么原因啊
2 楼 guilipan 2010-02-09  
jqgrid3.6版本以上才支持你上面注释的方法,3.6之前的版本你用下面的方法是可以的
3 楼 zuozhengfeng 2010-02-09  
后来没有办法把上面这个例子复制了,可以运行,再一行一行的增加,最终也就可以了,还不是很清楚上面原因,但是可以正常运行了
4 楼 konglx 2010-05-09  
哦,谢谢指点
  相关解决方案