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java如何读取json数据呢

热度:6907   发布时间:2013-02-25 21:51:49.0
java怎么读取json数据呢
java怎么读取json数据呢

------解决方案--------------------------------------------------------
json最好用js读取,非常方便,就跟处理对象一样简单

Java code
package test;import org.json.JSONArray;import org.json.JSONException;import org.json.JSONObject;public class StrJson1 {    public static void main(String[] args) {        String json = "{'name': '呵呵','array':[{'a':'111','b':'222','c':'333'},{},{'a':'999'}],'address':'上海'}";           try {            JSONObject jsonObject = new JSONObject(json);            String name = jsonObject.getString("name");            String address = jsonObject.getString("address");            System.out.println("name is:" + name);            System.out.println("address is:" + address);                       JSONArray jsonArray = jsonObject.getJSONArray("array");                       for (int i = 0; i < jsonArray.length(); i++) {             System.out.println("item " + i + " :" + jsonArray.getString(i));                  try{                     JSONObject jsonObject333 = new JSONObject(jsonArray.getString(i));                    String aaaa = jsonObject333.getString("a");                    System.out.println("----------"+aaaa);                  }catch(Exception e){                  }            }           } catch (JSONException e) {            e.printStackTrace();           }    }}
------解决方案--------------------------------------------------------
看个js的处理

XML code
{        userName: "nihao",        sex: "male",        age: "23"  }
------解决方案--------------------------------------------------------
这里就是json字符串,还算比较复杂的一个了吧 {"icache":[{"cache_server_address":"10.88.53.198:11201","app_name":null,"cache_server_id":null,"token":null},{"cache_server_address":"10.88.53.198:11200","app_name":null,"cache_server_id":null,"token":null}]}

先到http://download.csdn.net/source/3512951下载jar包,然后

private static List<String> getListFromJson(String json) {

JSONObject ObjList;
List<String> list = new ArrayList<String>();
try {
ObjList = new JSONObject(json);
if (ObjList.has("icache")) {
JSONArray jArray = ObjList.getJSONArray("icache");
for (int i = 0; i < jArray.length(); i++) {
JSONObject jObj = (JSONObject) jArray.get(i);
list.add(jObj.getString("cache_server_address"));
}
}
} catch (Exception e) {
logger.error(e);
list = null;
} finally {
logger.info("ServerList is " + list);
return list;
}
}
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