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发神经了,暴了一个org.apache.jasper.JasperException解决思路

热度:48   发布时间:2016-04-17 01:19:23.0
发神经了,暴了一个org.apache.jasper.JasperException

说明一下,我用webwork开发的,我写一个Tag类。要传一个Useres实体的属性。第,我在使用这个标签是<user:toolTag user="#session[user]"/>它就暴了这一个错。我怎么样将当session中的user为null时,不暴错呢?要是数据类型转不了。
如果用${user}这个更气,就是用了tomcat5.5就暴这个错,用了tomcat6.0就没有错。哎。。。。。

标签代码如下。
Java code
package com.gz.koal.sys.tag;import java.io.IOException;import javax.servlet.jsp.JspWriter;import javax.servlet.jsp.tagext.TagSupport;import org.apache.commons.logging.Log;import org.apache.commons.logging.LogFactory;import com.gz.koal.model.Useres;import com.opensymphony.xwork.DefaultActionInvocation;/** * 工具栏标签 * @author Administrator * */public class ToolTag extends TagSupport {    private static final long serialVersionUID = 1L;    private static final Log LOG = LogFactory.getLog(DefaultActionInvocation.class);        private Useres user=null;    public static long getSerialVersionUID() {                return serialVersionUID;    }    public Useres getUser() {        return user;    }    public void setUser(Useres user) {        this.user = user;    }        public int doStartTag()  {        JspWriter out=this.pageContext.getOut();        try {                        out.println("<div  align='right' style='background: #dfdddd'>");            if(user==null)            {                out.println("<a href='/webwork/jsp/login.jsp' target='_parent'>[登录]</a> ");                out.println("<a href='/webwork/jsp/register.jsp' target='_parent'>[注册]</a> ");                                            }else            {                                   out.println("<a href='/webwork/jsp/control.jsp' target='_parent'>["+user.getUserName()+"]设置</a>");                out.println("<a href='/webwork/user!undo.action'>[注销]</a> ");            }            out.println("<a href='/webwork/jsp/index.jsp' target='_parent'>[返回主页]</a>");            out.println("</div><br/>");                  } catch (IOException e) {            LOG.error("标签文件发生IO流异常"+e.getMessage());                    }catch(Exception e)        {            LOG.error("标签文件发生未知异常"+e.getMessage());        }        return SKIP_BODY;    }        }

2008-12-26 10:48:41 org.apache.catalina.core.ApplicationDispatcher invoke
严重: Servlet.service() for servlet jsp threw exception
org.apache.jasper.JasperException: Unable to convert string "#session['user']" to class "com.gz.koal.model.Useres" for attribute "user": Property Editor not registered with the PropertyEditorManager
at org.apache.jasper.runtime.JspRuntimeLibrary.getValueFromPropertyEditorManager(JspRuntimeLibrary.java:887)
at org.apache.jsp.jsp.index_jsp._jspx_meth_user_005ftoolTag_005f0(index_jsp.java:101)
at org.apache.jsp.jsp.index_jsp._jspService(index_jsp.java:70)

------解决方案--------------------
com.gz.koal.model.Useres 这里面有user属性吗 ??
还是session中没这个属性 ?还是没SET GET方法
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