先贴一下代码：
<%
UserContainer nameContainer=(UserContainer)session.getAttribute( "USER ");
String usertemp=(String)nameContainer.UserName;
int userPurview=nameContainer.Type;
String isAudit=null;
…………
%>
UserContainer类的定义
public class UserContainer
{
public int Index;
public String UserName;
public String Password;
public int Type;
public int BorderType;
……
}
用的是tomcat架设的服务器
给出的错误提示是;
org.apache.jasper.JasperException: An exception occurred processing JSP page /admin/left.jsp at line 15
12: <link href= "/css/style.css " rel= "stylesheet " type= "text/css ">
13: <%
14: UserContainer nameContainer=(UserContainer)session.getAttribute( "USER ");
15: String usertemp=(String)nameContainer.UserName;
16: int userPurview=nameContainer.Type;
17: String isAudit=null;
18: int tBID=nameContainer.BorderType;
我的session中的USER没有初始值 直接获取
为什么15行会出问题
------解决方案--------------------
if(nameContainer != null)
String usertemp=(String)nameContainer.UserName;
代码迷推荐解决方案：An exception occurred processing JSP page,http://www.daimami.com/search?q=33144