- Java code
<%@ page language="java" import="java.util.*,java.sql.*,bbs.*" pageEncoding="GB18030"%><% request.setCharacterEncoding("UTF-8"); int pid = Integer.parseInt(request.getParameter("pid")); int rootId = Integer.parseInt(request.getParameter("rootId")); String title = request.getParameter("title"); System.out.println(title); String cont = request.getParameter("cont"); System.out.println(cont); Connection conn = DB.getConn(); String sql = "insert into article values(?,?,?,?,sysdate,?)"; PreparedStatement pstmt = DB.prepareStmt(conn, sql); pstmt.setInt(1, pid); pstmt.setInt(2, rootId); pstmt.setString(3, title); pstmt.setString(4, cont); pstmt.setInt(5, 0); pstmt.executeUpdate(); DB.close(pstmt); DB.close(conn);%>String sql = "insert into article values(?,?,?,?,sysdate,?)";
这样写提示出错：
org.apache.jasper.JasperException: An exception occurred processing JSP page /replyDeal.jsp at line 24
21: pstmt.setString(3, title);
22: pstmt.setString(4, cont);
23: pstmt.setInt(5, 0);
24: pstmt.executeUpdate();
25: DB.close(pstmt);
26: DB.close(conn);
27: %>
javax.servlet.ServletException: java.sql.SQLException: ORA-00947: 没有足够的值
org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:865)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:794)
org.apache.jsp.replyDeal_jsp._jspService(replyDeal_jsp.java:122)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:386)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
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String sql = "insert into article values(null,?,?,?,?,sysdate,?)";
这样写提示出错：
javax.servlet.ServletException: java.sql.SQLException: ORA-01400: 无法将 NULL 插入 ("SCOTT"."ARTICLE"."ID")
org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:865)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:794)
org.apache.jsp.replyDeal_jsp._jspService(replyDeal_jsp.java:122)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:386)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
----------------------------------------------------------------------------
数据库里ID号设置的是自增的
create sequence seq_article increment by 1 start with 1;
到底是哪里出错了，求解.....
------解决方案--------------------------------------------------------
楼主 把sql语句换成这样子：
String sql = "insert into article values(seq_article.nextval,?,?,?,?,sysdate,?)";
------解决方案--------------------------------------------------------
你在插一条试试 ，看是不是接着增长的，
有数据插入过的，自增会自己从下一个开始
另外建议不使用自增长来做主键
------解决方案--------------------------------------------------------