题目
For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:1. The area of the rectangular web page you designed must equal to the given target area.2. The width W should not be larger than the length L, which means L >= W.3. The difference between length L and width W should be as small as possible.
You need to output the length L and the width W of the web page you designed in sequence.
Example:
Input: 4
Output: [2, 2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1].
But according to requirement 2, [1,4] is illegal; according to requirement 3, [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.
Note:
The given area won't exceed 10,000,000 and is a positive integer
The web page's width and length you designed must be positive integers.代码
这种思想类似于，先默认其为一个比原面积大的正方形，然后进行细微的调整
class Solution {public int[] constructRectangle(int area) {int w=(int)Math.sqrt(area);int l = w;while(w>=1&&l<=area){int t_area = w*l;if(t_area==area){return new int[]{l,w};}if(t_area > area){w--;}else{l++;}}return null;}
}此种方法相同的思想，不过其只用了宽进行调整，找到尽可能的大的宽度，然后与area相除即可得到长
因为(int) Math.sqrt(area)之后抹掉了余数，所以宽度永远没有长度大。
class Solution {public int[] constructRectangle(int area) {int w = (int) Math.sqrt(area);while(area % w != 0) {w--;}return new int[] {area/w, w};}
}