Sqlserver ，Oracle获取sql查询时间最长的语句

SQL Server：

SELECT TOP 100total_worker_time/1000 AS [总消耗CPU 时间(ms)],execution_count [运行次数],qs.total_worker_time/qs.execution_count/1000 AS [平均消耗CPU 时间(ms)],last_execution_time AS [最后一次执行时间],max_worker_time /1000 AS [最大执行时间(ms)],SUBSTRING(qt.text,qs.statement_start_offset/2+1, (CASE WHEN qs.statement_end_offset = -1 THEN DATALENGTH(qt.text) ELSE qs.statement_end_offset END -qs.statement_start_offset)/2 + 1) AS [使用CPU的语法], qt.text [完整语法],dbname=db_name(qt.dbid),object_name(qt.objectid,qt.dbid) ObjectName
FROM sys.dm_exec_query_stats qs WITH(nolock)
CROSS apply sys.dm_exec_sql_text(qs.sql_handle) AS qt
WHERE execution_count>1
ORDER BY  total_worker_time DESC

Oracle：

select *from (select sa.SQL_TEXT,sa.SQL_FULLTEXT,sa.EXECUTIONS "执行次数",round(sa.ELAPSED_TIME / 1000000, 2) "总执行时间",round(sa.ELAPSED_TIME / 1000000 / sa.EXECUTIONS, 2) "平均执行时间",sa.COMMAND_TYPE,sa.PARSING_USER_ID "用户ID",u.username "用户名",sa.HASH_VALUEfrom v$sqlarea saleft join all_users uon sa.PARSING_USER_ID = u.user_idwhere sa.EXECUTIONS > 0order by (sa.ELAPSED_TIME / sa.EXECUTIONS) desc)where rownum <= 50;